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Re: [Amps] Relay rewinding

To: "Svante Nordenstrom" <sm3dyu@ji-net.com>
Subject: Re: [Amps] Relay rewinding
From: "Will Matney" <craxd1@ezwv.com>
Date: Fri, 14 Jan 2005 11:47:51 -0500
List-post: <mailto:amps@contesting.com>
Sam,

The link provided earlier is correct in winding DC relays. I'll try to explain it in a little simpler terms (theory). A DC relay acts different than an AC relay in the current drawn in the coil because of different impedances. In other words, an AC coil has inductance and a DC coil has resistance. The trick to winding the DC coil is having enough wire in length to provide enough resistance that it wont burn out with a DC current applied. Also, to have enough magnamotive force to pull in the armature of the relay. To get this high amount of resistance, you end up with anywhere of a few hundred feet to maybe a thousand feet of wire to get enough resistance for the right DC current at the operating voltage. This is where the ampere turns comes in but it is different between AC and DC due to the difference between inductance and resistance.

Best,

Will

On Fri, 14 Jan 2005 15:47:40 +0700, Svante Nordenstrom <sm3dyu@ji-net.com> wrote:

Hi all
I have a number of brand new coax relays, brand Bernier type LMT/B/1023526/2
with N-type connectors. They are NO configured and makes when power, which
somewhere between 60 to 110V DC, is applied. The coil has a DC resistance of
4.5 kohm with the dimensions 50 x 25 mm outer measurements of bobbin (Sorry,
I'm metric). Can anybody give a rough figure of what size wire and number of
turns to make it a 12VDC relay? I don't have any relevant books for this
kind of calculations and I am probably too rusty in the math anyway..
73's
Sam HS0ZDY




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