To: | "Amps@contesting.com" <Amps@contesting.com> |
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Subject: | Re: [Amps] Plate impedance formula |
From: | "Will Matney" <craxd1@ezwv.com> |
Date: | Sun, 06 Feb 2005 10:52:04 -0500 |
List-post: | <mailto:amps@contesting.com> |
George, Well, it's according to what the total plate current is. Let's say you had one tube drawing 100 mA. Then you add another drawing the same. That would then be 200 mA which then would divide the resistance in half. However, if you had the same two tubes and cut them back so each would draw 50 mA, it would be the same as 1 drawing a 100 mA. I should add that those values are for peak plate current and peak voltage. I also seen another ham in Europe using a modified formula with the k factor of something like 1.87 or 1.89. He claimed it got it closer to the true values when calculating the tank circuit for a class AB1 amp. The published K factor is 1.8 in most books and the RCA tube books. Best, Will On Sun, 06 Feb 2005 07:18:29 -0500, George KB2Z <Thermionic_Emission@earthlink.net> wrote: Will, For the way the output tank sees it, in a common 2 tube amp, would that value double, half, or stay the same? Thanks, George
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