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Re: [Amps] Measuring RF Power

To: "amps@contesting.com" <amps@contesting.com>
Subject: Re: [Amps] Measuring RF Power
From: David Kirkby <david.kirkby@onetel.net>
Date: Sat, 26 Mar 2005 02:12:50 +0000
List-post: <mailto:amps@contesting.com>
R. Measures wrote:

>>>
>>> The right answer is that RMS current x RMS potential = AC P
>>
>>
>> Any chance of you substantiating what you have said?
>
>
> Does P = I x E? 

Rich,

I asked you to substantiate why you said K4FMX was wrong when he said 
you can not find RMS power by multiplying RMS voltage by RMS current. 
That should not need me to answer a question.

You have in the past gone to great lengths to try to back up your views 
on parasitic oscillations - is it asking too much to ask you to 
substantiate something as simple as power in a resistor?

I think Gary is right, and you are wrong, and I have rigorously proved 
that.

In any case, it would be pointless for me to try to answer your question 
when nothing  is not defined properly.

-- 
Dr. David Kirkby, 
G8WRB

Please check out http://www.g8wrb.org/ 
of if you live in Essex http://www.southminster-branch-line.org.uk/



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