Yes, that should be 3000 divided by 1.8 = 1666.6 ohms.
In this case power equals current squared times load resistance which is
1666.6 watts. This power level is consistent with 3000 watts input and 55.5%
efficiency. If the load was 5400 ohms we would be generating 5400 watts of
power
which is more than the power input; this is of coarse impossible.
73/k5gw
In a message dated 4/10/2006 4:43:24 P.M. Central Standard Time,
on4kj@skynet.be writes:
n
5400 ohms plate load
calculating using the K factor stuff.
3000v/1A/1.8 is equal to 1666 ohms so one of your numbers is flawed.
3000 X 1.8 = 5400 is there any relation to be aware of ?
Jos
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