Jim,
I have done this calculation several times so maybe someone else will do
it as verification. Using the temperature rise I posted and your
example of 1500W & 1/2 gal. water starting at 50deg F would boil in
(2000/1500)*(1/2)*(162/13.7) = 7.88 min. (not the 11.8 min. you
calculated). Maybe you are boiling a little less than 1/2 gallon, or
your heater is a little higher than 1500W or the initial water temp is a
little higher than 50 deg. F or maybe I made a mistake.
I would bet on the 1500W heater which is probably rated for 120/240V or
117/234V and most line voltages today have risen to 125/250V. 117V to
125V change would change the 1500W heater into a 1712W heater.
Any one want to check my math?
Larry, W0QE
On 6/6/2013 10:58 AM, Jim Thomson wrote:
Date: Thu, 06 Jun 2013 08:24:58 -0600
From: Larry Benko <xxw0qe@comcast.net>
To: amps@contesting.com
Subject: Re: [Amps] Advice needed for SS amp
2000W of power(heat) into 1 gallon of pure water raises the temperature
7.7deg. C (13.7deg. F) per minute. Anything you do to water such as
mixing in alcohol reduces the cooling capacity somewhat. In a total
loss system where the water would be run through the amp and then out
into the garden a flow of 1 quart (or ~ 1 liter) per minute would suffice.
Larry, W0QE
## are you sure about that ? IF the cold tapwater was 50 F, it would take
11.8 mins to reach
boiling. It does not take more than 5 mins to boil 1/2 gallon of water in my
1500 w kettle.
Jim VE7RF
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