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Re: [Amps] 8877 input Z

To: amps@contesting.com
Subject: Re: [Amps] 8877 input Z
From: Larry Benko <xxw0qe@comcast.net>
Date: Fri, 28 Mar 2014 12:48:23 -0600
List-post: <amps@contesting.com">mailto:amps@contesting.com>
If the load is 50 ohms (using 50 just for example purposes) in parallel with 42pF a series inductance matches well enough that a given inductance will be good for more than 1 band. However if you add another 42pF shunt capacitor from the exciter side of the inductor and change the inductance to about 91nH the circuit will match from 1.8 to 30MHz with a maximum exciter SWR of 1.15:1 with NO switching required at all. If you want it even lower a combination low pass and high pass "L" network can be done (only 1 more component).

73,
Larry, W0QE


On 3/28/2014 11:54 AM, TexasRF@aol.com wrote:
Hardy, the 54 ohms is a nominal figure that will vary with rf drive level.
Certainly close enough for designing input networks. Higher drive levels
will  result in a lower input impedance; lower drive levels will result in a
higher  input impedance.
The 42 pF is the capacitance between the cathode and grid primarily. So,
you will need to provide an inductance to cancel that out. The inductance
will  be different for each band of course.
73,
Gerald K5GW
In a message dated 3/27/2014 7:55:49 A.M. Pacific Daylight Time,
n7rt@cox.net writes:

I am  looking for the input impedance of an 8877. I found one source and
that was  K6DC's (SK) article years ago that said it was 54 ohms with no
frequency  dependency or reactive component. The input C is 42 pF according to
the data  sheet. So I will assume I can use 54 ohms in parallel with 42 pF.
Anyone have  anything different?
73 Hardy  N7RT
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