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>From : firstname.lastname@example.org
To : email@example.com
Date : Tue, 21 May 2002 14:09:54 +0100
Subject : [Antennaware] Cylindrical Model for Triangular Tower
> Somewhere I got the following formula for a cylindrical
> equivalent to triangular tower like Rohn 45.
> Equivalent Cylindrical Diameter = 2 * CUBEROOT [(D * F^2)/2]
> where D = tube diameter and F = Face width. For Rohn 45, D = 1.25"
> and F = 18", so cylindrical diameter equivalent = 11.7446"
> Does anyone know where this came from or if it is valid?
> 73, Bill W4ZV
I'd make a scale model using a triangular and cilindical profilate on a
convenient frequency (i.e. VHF) to verify if the approximation in
object is reasonable.
Note anyway that in case of consistent top loading the cylindrical
equivalent to triangular of the vertical section is a secondary