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Subject:  [Antennaware] Cylindrical Model for Triangular Tower 
From:  john.w1fv@telocity.com (John Kaufmann) 
Date:  Tue, 21 May 2002 09:10:56 0700 (PDT) 
Bill Tippett wrote: > > > Somewhere I got the following formula for a cylindrical > > equivalent to triangular tower like Rohn 45. > > > > Equivalent Cylindrical Diameter = 2 * CUBEROOT [(D * F^2)/2] > > > > where D = tube diameter and F = Face width. For Rohn 45, D = 1.25" > > and F = 18", so cylindrical diameter equivalent = 11.7446" > > > > Does anyone know where this came from or if it is valid? This formula originally appeared in the IEEE Transactions on Broadcasting. I posted a note about it on this reflector back in 1998. See: http://lists.contesting.com/_antennaware/1998October/000133.html. 73, John W1FV 
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