-=> Quoting W9IP: screw-in guy anchors<=-
Mo> so : r = 122 * 0.7 = 85.5 cm
Mo> Vol = 1/3 * 3.14 * (85.5)^2 * 122 = 925,000 cm^3 (more or less)
Mo> Weight = 925,000 cm^3 * 1.5 g/cm^3 = 1,387,500 g = 1,388 kg
Mo> which is about 3,000 lbs. [ notice that this figure drops
Mo> *rapidly* if you don't screw the thing in all the way ]
Mo> Class dismissed.
Mo> MRO
Thanks Mike, I'll forward this to the Rohn Engineering Dept!
>From Victor Budyukin <victor@victor.krasnoyarsk.su> Wed Aug 17 12:22:56 1994
From: Victor Budyukin <victor@victor.krasnoyarsk.su> (Victor Budyukin)
Subject: Packet and real SO contetsing
Message-ID: <AAGCVKkSr1@victor.krasnoyarsk.su>
Hi, guys!
About this packet radio SO question why not let our computers operate
our radio during the contest and we will call this category "0.5 Operator".
We will go fishing and upon our return check our score. Why not guys?
73 de Pete
RA0A/K4EWG
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