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[TowerTalk] 20 Meter

 To: [TowerTalk] 20 Meter W8JI@contesting.com (Tom Rauch) Mon, 5 Mar 2001 19:45:28 -0500
 ```> unproper linear loading arrangements. Back to the matching circuits, > they may introduce losses when some of their elements have losses, > tipically a gamma capacitor with a lossy dielectric @ 28 MHz is one of > the the worst cases for HF, or when the mechanical construction (i.e. I'm not aware of any gamma capacitors that employ lossy dielectrics, mostly because lossy systems would be self- eliminating at the power levels we run. Most dielectrics are polyethylene, which is one of the lowest loss materials available. As in a transmission line at HF, dielectric losses are not a factor. The gamma match does not carry significant current, no matter what impedance element it is matching. It does not matter if the element's loop radiation resistance is 5 ohms or 45 ohms, the gamma rod sees 50 ohms. Current in the gamma capacitor is never more than the current in the 50 ohm line feeding the antenna, and voltage across the gamma capacitor is the reactance times the 50 ohm transmission line current...which has nothing to do with loop radiation resistance of the element. > with an hairpin) involves a number of different parts with several > joints and the impedances in those points is already rather low. > Although nothing fails and noone notices the heath, or neither a > signal decrease is roughly appreciable, when discussing about marginal > gains like 0.25 or 0.5 dB (a 5% or 10 % of the power) already a simple > 0.5 Ohm series resistance in a 20 OHm radiator adds an extra .22 dB > loss. While it is true the current is maximum in the hairpin, if we lost 5 or 10% of the power in a joint or a few joints in the antenna we would certainly have problems. Imagine 150 watts of heat distributed in perhaps two connections, and picture how hot the tiny surface area of those connections would become. My L-network matching the common point of a phased array has a feed impedance of approximately 20 ohms, and it uses only a ten turn #8 AWG inductor bolted to a capacitor. The losses in that L network, which are substantially more than I expect from a reasonable size hairpin conductor, produce less than 30 watts of heat out of 1500 watts applied. Most of the joints in a traditional hairpin are at lower current areas of the a hairpin, at the 50 ohm point of the system. Most hairpins of good design do NOT interrupt the conductor at the highest current area. It makes no sense to redesign an antenna to raise the feedpoint impedance to 50 ohms and give up performance, when any small losses in matching could easily be handled through simple proper construction techniques. I'm reminded of Lew McCoy's silly article a few years ago in CQ Magazine about terrible loss in yagi elements, and his suggestion that a #16 wire element has less loss than 1"diameter aluminum tubing because the wire "has no lossy joints". With ten ohms, we only deal with 12.5 amperes. These are not small loop antennas with radiation resistances of .05 ohms and hundreds of amperes of current, where pressure joints do become a mensurable problem. 73, Tom W8JI W8JI@contesting.com -- FAQ on WWW: http://www.contesting.com/FAQ/towertalk Submissions: towertalk@contesting.com Administrative requests: towertalk-REQUEST@contesting.com Problems: owner-towertalk@contesting.com ```
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