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## [Towertalk] Statics 101

 To: [Towertalk] Statics 101 K3BU@aol.com (K3BU@aol.com) Fri, 12 Jul 2002 00:04:51 EDT
 ```In a message dated 7/11/02 8:15:40 PM Eastern Daylight Time, wendell@wyly.org writes: > > Don't matter how many pulleys you use, unless you make a second attachment > to the tower you don't gain anything as the ground crew holds the rope (same > as tieing it to a ground) and the gin pole takes out twice the load since > there are two equal downward force vectors. It "do's" matter! (According to "mechanics 1001" :-) If you use two pulleys, one pulley at the bottom (with one end of rope tied to the top of tower, the other end looped through pulley at the bottom and over the pulley at the top) then your 100 lbs is (more-less, assuming well oiled pulleys) divided between two ropes going over the bottom pulley, and you are pulling with abt. 50 lbs force at the pulling rope (twice distance). The load on the gin pole is 150 lbs (assuming the top end of rope is tied to the gin pole. If you tie the top end to the tower, say, below gin pole and top pulley is tied to the gin pole, then gin pole gets abt. 100 lbs load (50 from you pulling, 50 from half of rope going over bottom pulley). Way to minimize the stress on the gin pole. Of course, pulling straight down minimizes the bending moment on the gin pole. Formula for pulling force F = 1/n x W, where W is the weight of antenna at the end of block, n is the number of ropes in the block (not counting one you are pulling). I have been using two pulleys at each end (gave me F = 1/4 W) to lift my 62 ft boom Razors by myself, with pulling rope threaded through loop at the hook, guiding the antenna away from the tower. Big Bertha tower with no guys helped. Wear hard hat, things fall from the tower. Yuri, K3BU ```
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