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## [TowerTalk] Guy location correction

 To: [TowerTalk] Guy location correction henry@mrlistersir.com (Henry) Thu Jun 12 16:04:59 2003
 ```If you do as mentioned, "take the length from the tower to the guy and double it", you'll be off by a factor of 3^(1/2)/2 or about .87. Remember your HS trig and the relationship of the sides of a 30-60-90 triangle. Then you have to orient the triangle correctly on your plans. The hypotenuse is the distance from the tower to the guy anchor, the long leg is half the distance from guy anchor to guy anchor. The relationship of the triangle is hypotenuse = 1 short leg = 1/2 long leg = 3^(1/2)/2 or about .87 for example, if the distance from the tower to the guy anchor is 50ft. The distance from anchor to anchor will be (2)(.87)(50)ft. + 85ft. This result is very different from 2 x 50ft = 100ft. Given the tolerance levels needed here, Steve's method probably is the easiest. Given that I'm a HS math teacher and am in math grad school. It's a bit easier for me to remember my HS trig. end Henry KB7RTA henry@mrlistersir.com ```
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