In a message dated 6/19/03 4:42:27 PM Eastern Daylight Time,
towertalk-request@contesting.com writes:
> Ok, mathemeticians and engineers out theree.. I need some help
>
> Have an MA-550 55' tower. I have a little over 7 sqr feet of antenna. A
> Steppir (6sqr ft), a 40m D40 cushcraft dipole (1sqr ft) and a 2/440 verticle
> (<0.25sqr fet).
>
> The The wind load capacity of the MA-550 at 50mph is a little more than 10
> sqr feet of antenna and at 80mph it is around 6sqr feet. This is based on
> the antenna being around foot or so above the top of the tower. If I use
> their 20ft reinforced steel mast and put the 3 element Steppir at 10 feet
> above
> the top of the tower and the D40 at the top, at 20 feet above. What does
> that
> do to it's wind loading capacity?
>
> Michael
============
Michael,
A simple calculation is to ratio the height of the antenna attachment point
times the known antenna area. or 6 * (1+54)/(9+54) = new area or
6*(55/63)= 5.2sq ft.
Regards,
Norman W4QN
"The Power of a Cubex Quad"
<A HREF="http://www.cubex.com/";>http://www.cubex.com/</A>
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