I asked the same question some time ago.
The answer I received was.
Subtract one square foot for each foot above the top of the tower.
So in the case of 10 Square feet at 50 Mph.
10 feet above the top of the tower you can have 0 square feet of antenna.
5 feet above the top of the tower you can have 5 square feet of antenna.
At the top of the tower you can have 10 square feet of antenna.
For the 6 square feet at 80 Mph.
6 feet above the top of the tower you can have 0 square feet of antenna.
3 feet above the top of the tower you can have 3 square feet of antenna.
At the top of the tower you can have 6 square feet of antenna.
Most installations don't seem to follow these guide lines.
----- Original Message -----
From: "Michael Hatzakis, Jr" <email@example.com>
Sent: Thursday, June 19, 2003 6:09 PM
Subject: [TowerTalk] US Towers and wind Loading Capacity
> Ok, mathemeticians and engineers out theree.. I need some help
> Have an MA-550 55' tower. I have a little over 7 sqr feet of antenna.
A Steppir (6sqr ft), a 40m D40 cushcraft dipole (1sqr ft) and a 2/440
verticle (<0.25sqr fet).
> The The wind load capacity of the MA-550 at 50mph is a little more than
10 sqr feet of antenna and at 80mph it is around 6sqr feet. This is based
on the antenna being around foot or so above the top of the tower. If I use
their 20ft reinforced steel mast and put the 3 element Steppir at 10 feet
above the top of the tower and the D40 at the top, at 20 feet above. What
does that do to it's wind loading capacity?
> Michael Hatzakis, Jr MD
> Physiatrist, Treating Individuals with Neuromuscular Disabilities
> Consultant, Information Technology Based Health Care Solutions
> Do you Yahoo!?
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> See: http://www.mscomputer.com for "Self Supporting Towers", "Wireless
Weather Stations", and lot's more. Call Toll Free, 1-800-333-9041 with any
questions and ask for Sherman, W2FLA.
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