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## RE: [TowerTalk] kt34xa torque balancing

 To: "TowerTalk" RE: [TowerTalk] kt34xa torque balancing W0UN -- John Brosnahan Sun, 09 Jan 2005 07:17:54 -0600
 ```Jim Jarvis and I have had a couple of off-line exchanges. This is a note I wrote to him to try and make sure we both are talking about the same thing. (As my late partner used to say -- A word is worth a milli-picture!) And after writing the note I decided the concept of a single, asymmetrical element might make the cross-flow principle easier to understand for anyone who might still be having difficulty. My apologies to anyone who is getting bored with all of this. But it IS an important topic since the analysis has been done incorrectly by the ham antenna manufacturers for so many years. I hope my word picture-- without any mathematics (or drawings!)--makes it all a bit easier to follow.``` ```--John ---------------------------------------------------------------``` Hi, Jim-- ```I am not sure if we are in agreement or not, but let me show you the ad absurdum case to make sure we are both talking apples.``` ```Take a 40 ft boom (arbitrary) of 3 inch tubing and attach it to the mast in the exact center. Now attach, ala the old Telrex method, a single element (oh, say a 20M reflector) at one END of that boom. (Telrex style element used to greatly reduce any quibble about mounting brackets, since Telrex ran their elements through the boom.)``` ```OK, so far? Only ONE element and it is at the very end of the boom, 20 ft from the mast. It LOOKS like a classic weather vane doesn't it, because of total asymmetry. BUT it needs NO torque balancing!``` Wind hitting one half of the element (no matter the angle) will produce a vector force that can be defined as the sum of two vectors -- one perpendicular to the element and one parallel to the element. The parallel vector has NO effect on the element--wind has no "stiction". The perpendicular vector on one half of the element gets transferred as a force trying to rotate the element in a counterclockwise direction. BUT the same wind on the other half of the element also gets broken down into the same two vectors and the parallel vector once again can be ignored. The perpendicular vector also gets transferred to the boom, but this time in a clockwise direction. ```Or just take your hand and push on one side of the element and see how the force tries to push on the boom. Doing the same thing on the other side with your hand will also push on the boom but in the opposite direction. The two forces balance.``` ```In reality it is MUCH more complex but it is not what has typically been modeled. For instance, take a 45 degree wind to the element. The upwind side will WANT to bend in such a way as to become MORE broadside to the wind. And the downwind side of the element will want to bend in such a way as to become less broadside to the wind -- just due to the fact that they are attached on opposite ends. One half is attached to the boom on the downwind end and one half is attached to the boom on the upwind end.``` But this effect is zero for a completely straight (stiff) element, and only plays a role when the elements are bending a lot on the wind. And if they bend more in the wind it is probably because they are thinner -- and have less wind area to start with. ```So, to first order, assuming the elements stay straight under the force of the wind, then there is NO need to compensate for any elements -- even if there is only ONE element at one end of the center-mounted boom.``` ```Element flex adds a small extra thing to think about as does any element projection that has any surface area parallel to the boom, such as the end cap on traps. The bodies of the two traps in an element cancel each other out since they are parallel to the element. But both upwind ends of any set of trap end caps will add to the load on the boom. But once again this is a pretty small area and the resulting forces are very low.``` So, to first order at least, you can ignore the elements and only compensate the boom if it is off center mounted to the mast. Or better still, mount the boom in the center and add some weight to one half to balance the boom. OK? ;-) 73--John _______________________________________________ See: http://www.mscomputer.com for "Self Supporting Towers", "Wireless Weather Stations", and lot's more. Call Toll Free, 1-800-333-9041 with any questions and ask for Sherman, W2FLA. ```_______________________________________________ TowerTalk mailing list TowerTalk@contesting.com http://lists.contesting.com/mailman/listinfo/towertalk```
 Current Thread Re: [TowerTalk] Torque balancing made easy, was kt34xatorque balancing, (continued) Re: [TowerTalk] Torque balancing made easy, was kt34xatorque balancing, W0UN -- John Brosnahan Re: [TowerTalk] Torque balancing made easy,was kt34xatorque balancing, K8RI on Tower Talk Re: [TowerTalk] Torque balancing made easy,was kt34xa torque balancing, Michael Tope Re: [TowerTalk] kt34xa torque balancing, Michael Harris [TowerTalk] kt34xa torque balancing, Jim Jarvis Re: [TowerTalk] kt34xa torque balancing, W0UN -- John Brosnahan RE: [TowerTalk] kt34xa torque balancing, Tod - Minnesota RE: [TowerTalk] kt34xa torque balancing, W0UN -- John Brosnahan Re: [TowerTalk] kt34xa torque balancing, W0UN -- John Brosnahan Re: [TowerTalk] kt34xa torque balancing, Cqtestk4xs RE: [TowerTalk] kt34xa torque balancing, W0UN -- John Brosnahan <= [TowerTalk] Torque balancing, Red Re: [TowerTalk] Torque balancing, Gene Smar RE: [TowerTalk] kt34xa torque balancing, Tod - Minnesota