Noel, 3.6 uH has a series reactance of about 40 ohms; a Q of 289 equates to
a series loss resistance of about 40/289 or about .14 ohms. At 1500w there
could be about 6.5 amps of current flowing through the inductor. Loss power
then
would be about 6.5 squared times .14 or about 6 watts.
6 watts lost will make no discernable signal strength difference so the only
consideration is if the inductor can safely dissipate the power without self
destructing. If located inside a small air tight enclosure, this might be a
problem; mounted in the open or larger enclosure, not a problem.
73,
Gerald K5GW
In a message dated 3/4/2007 12:19:28 P.M. Central Standard Time,
ve2ryy@globetrotter.net writes:
I am on the way of building the three element parasitic array on 160 meter
according to ON4UN LowBandDxing book.
In the array, there is a parasitic element which is a Director...(1.935Mhz)
This same element is used for Reflector by installing an inductance of
3.6UH between the bottom end of the parasitic and the ground...
Now here is the question.
When making this inductance, do I have to take account of the Q factor .
I have made one just for fun, with nr 14AWG wire ...etc....
I get the right inductance needed, but I find that the Q factor is not very
high, say about 289 plus or minus....
Again this inductance is not going to be in the driven element, it is going
to be in the parasitic, located about 66 feet away from the driven element..
I would appreciate any comments about the Q Factor in a parasitic
element....
Thanks
NOEL
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