I agree with your conclusions Dan, and with your first explanation.
Since you got me on that one, just for the sake of argument, I will pick
on your last statement.
..."I think the meter is fine. There's more current in one leg than the
other because of common mode current,".....
Well not exactly. Common mode current does not cause more current in one
leg than another. Common mode current can be a result of the
differential currents not being equal and opposite, but it is also
possible to have common mode currents plus have matched differential
mode currents, although I can't think of a good example of this with
antennas. It is more often found in circuits where there is more than
Yeah, I know that is probably not exactly what you meant to say.
Dan Zimmerman N3OX wrote:
>>. It should be measuring
>>current balance between the two output lines, and this should be only a
>>function of the load.
>If you have a current imbalance on open wire line, you have common
>mode current. Only in the perfectly balanced case (equal and opposite
>currents) is the line operating with differential mode currents only.
>I think the meter is fine. There's more current in one leg than the
>other because of common mode current, but it's not the antenna's
>fault... the antenna is nice and symmetric (the switching of the
>output leads proves that )
>The test described in the original post says that the rig and tuner
>are not symmetrically sourcing current to the perfectly symmetric
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