N7KA@comcast.net wrote:
> Here is some differnt info.
>
> http://www.amphenolrf.com/products/typen.asp?N=0&sid=48B3478041F8E17F
That data (0.15 dB @ 10 GHz) implies that the K in Joe's equation should
be a bit less than 0.05, rather than 0.5
>>
>>
>> Joe Reisert, W1JR wrote:
>>> Hi Manius,
>>>
>>> The insertion loss of a good N connector is equal to the square root
>>> of F (in GHz) times a constant (K).
>>>
>>> The constant for a single N connector is 0.5. Therefore, at 23 CM
>>> (1.3 GHz) the loss is approximately .057 dB so you can add up the
>>> losses based on your situation.
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