> Is there someone, here, who can direct me, or tell me, how to convert,
> or would convert 600N to sq ft wind load.
> I have acquired a Titanex DLP-18, log periodic, and want to make sure
> my tower can handle it. The only information I can find, is from the
> web site, which states: 600N @ 120km/h. I can convert the km/h to
> around 75mph. Titanex has given me, absolutely, no response to numerous
> requests for information.
That's because Titanex is actually giving you useful engineering data..
a load at a velocity.
600 N * 1/4.5 lb/N = 133 lb
You're asking to convert a single data point into an equivalent area,
which, in turn, you're going to estimate loads for a different wind
The rough approximation is
force (lb) = (mph)^2/391 * area (sf)
so, 133 = 75^2/391 * area -->
About 9-10 square feet flat plate area will produce a force of 600N in a
wind of 120km/hr
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