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## Re: [TowerTalk] Equivalent wind load to square ft

 To: towertalk@contesting.com Re: [TowerTalk] Equivalent wind load to square ft Jim Lux Thu, 27 Oct 2011 07:34:35 -0700 mailto:towertalk@contesting.com>
 ```On 10/27/11 6:56 AM, Cqtestk4xs@aol.com wrote: > A friend of mine is thinking of putting up some wind generators and has > asked for my advice. The only information he can give me for the wind load > is 300# at 100 MPH. I know that makes sense to some, but I'm used to square > ft loads for ham antennas. What they have done is calculate the total load at 100 mi/hr. A rule of thumb is that wind load in pounds is Area(sq ft)* windspeed (mi/hr)^2/391 So, his windload at 50 mi/hr would be 75 lbs. However, this makes the assumption that the drag coefficient is constant (that is, that the drag goes as the square of the airspeed), which is probably not true for a wind generator, and certainly isn't true for something like a round tube at airspeeds we see. the real equation is Force = rho*Cd*A*v^2, where rho is the density of the fluid (air) Cd is the drag coefficient A is the area v is the fluid speed. The problem is that Cd varies quite a lot with speed, for low speeds (tens of mi/hr) and common dimensions (inches). What most people do is either assume Cd=1 (a sort of tending to the worst case) or take the worst case Cd (say, 1.3) and increase the "effective area" by that amount, so you can use the equation assuming Cd=1 > > Is there some kind of simple equivalency that I can use to figure out what > this would mean if we were talking plain old square ft antenna load? I > don't know if I worded this exactly right but I hope someone can help me on > this. What a tower designer does is take the "design wind speed" and the "maximum force" and work backwards to a square footage rating. Here's an example... Say the tower is designed for 70 mi/hr winds AND can take a 100 pound load at the top. The designer plugs in: A = 100*391/70^2 = about 8 square feet. Then they publish that in their spec sheet: "Can hold an 8 square foot antenna at 70 mi/hr" (but of course, the real design limit is some force... whether it's an antenna in the wind or a winch cable from your evil neighbor pulling the tower over, it doesn't matter to the tower) So, if you wanted to convert your friend's wind generator into an "equivalent antenna area" at 100 mi/hr, you do the same thing: 300 * 391/100^2 = 11.7 square feet. ---- A note about wind load ratings.. For many towers, the tower itself has more area than the antenna. This is especially true for home TV antenna type towers which can't take very much antenna at all. Since most of the load on the tower is from wind pushing on the tower, as opposed to the antenna, my example of the equivalency of winch cable and wind load isn't quite right. Your evil neighbor will have to pull MUCH harder to pull your tower down, than the few hundred pounds rated antenna wind load. _______________________________________________ _______________________________________________ TowerTalk mailing list TowerTalk@contesting.com http://lists.contesting.com/mailman/listinfo/towertalk ```
 Current Thread [TowerTalk] Equivalent wind load to square ft, Cqtestk4xs Re: [TowerTalk] Equivalent wind load to square ft, Jim Lux <= Re: [TowerTalk] Equivalent wind load to square ft, henry.lonberg Re: [TowerTalk] Equivalent wind load to square ft, Steve London