On 12/27/2011 04:30 PM, David Gilbert wrote:
> Fundamentally, when RF hits a conducting element (wire, piece of tubing,
> tree, side of a building, etc) it induces currents in that element ...
> currents that are no different than if you had been able to somehow
> connect your transmit coax to it. Those currents generate an
> electromagnetic field around that element that is in fact re-radiated
> RF. If the element is lossy (wood, dirt, wet mattress, etc) the induced
> currents are dissipated as heat instead of being re-radiated.
I think I get it now...
1) If the element is very low resistance, the RF will
induce a lot of current, but it will get re-radiated.
2) If the element is medium low resistance, the RF
will induce a fair amount of current, but it will
3) If the element is very high resistance, the RF
will induce very little current. You do not care
that it is absorbed, because it is so little.
Is this a fair synopsis?
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