HI,
L1 has much greater, internal circulating currents than L2 has. With typical
loaded Q's, L1 could easily have ten times the current of L2.
73, K6XK
-----Original Message-----
From: JWebs3939@aol.com <JWebs3939@aol.com>
To: amps@contesting.com <amps@contesting.com>
To: <amps@contesting.com>
Date: Tuesday, February 09, 1999 3:14 PM
Subject: [AMPS] PI-L network inductor wire sizes
>
> In a PI-L output network, is the RF current the same or different in the
PI
>inductor (L1) and the L inductor (L2) ?
> On the one hand, it would seem that the currents would be the same
since
>the inductors are in series. However on the other hand, since the network
is a
>stepdown impedance transformer, it would seem that the current in L2 would
be
>greater than in L1 due to the transformer action.
> In most of the amp designs that I have seen, the 10 meter portion of L1
>typically is 1/4" tubing and the 10 meter portion of L2 is #12 gauge wire.
> If the current is the same or greater in L2, why shouldn't the
conductor
>of L2 be at least as large or larger than that of L1 ?
> Thanks to anyone who can clear this up for me.
> 73 Don K9MUF
>
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