>
>On Wed, 28 Jul 1999 15:35:10 -0400 "Tom Rauch" <w8ji@contesting.com>
>writes:
>>> Incidently, I don't believe that recovery time is an issue in any 60 Hz
supply.
>>
>>Hi Marv,
>>
>>Then what determines the voltage division at the moment of
>>transition to cutoff?
>>
>
>Hi Tom,
> Well, in a (un-equalized) series string the fastest (recovery) diode
>will take the entire inverse voltage at that moment.
>
Only in your the world of imagination. In the non-Rauchian world,
avalanche voltage limits potential across each diode.
> ......
Rich...
R. L. Measures, 805-386-3734, AG6K, www.vcnet.com/measures
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