BTW, I did try to simulate the result using the 3.4 v p-p signal generator.
I've had some issues believing the result as it seems my signal generator
actually produces -1.7 to +1.7 v pulses. This makes me think there may be
a difference to something truly 0 to + 3.4 V pulses which the diodes may see.
----- Original Message -----
From: "Paul Decker" <kg7hf@comcast.net>
To: amps@contesting.com
Sent: Monday, March 30, 2009 5:37:17 PM GMT -05:00 US/Canada Eastern
Subject: winding an HV transformer
I've been holding this question for a couple of days now, I'm sure it is very
simple and perhaps I just need some reassurance on the answer.
If you have been following some of this smps discussion, I've got 100Khz pulsed
DC (0 - 340v) which is generated by directly rectifing and filtering the 240 V
AC mains and providing that into an h-bridge. The h-bridge dumps the 340 V
100Khz square wave into the transformer.
As the QST article recomends, I've wound the transformer with five turns on the
primary and had calculated that I need 30 turns on the secondary. Performing
some small signal tests, inputting 3.4v pk-pk square wave from my signal
generator yeilds about 20.4 volts pk-pk square wave. I believe this
relationship should be linear and inputting 340 V will yeild 2040 volts on the
secondary.
At this point the secondary dumps into a full wave bridge rectifier followed by
a filter capacitor. This is where I am unclear. When I rectify this with
the full wave bridge, will I get 2040 * 0.90 or will I get 2040 * 1.414 as the
final DC output? Part of me says I get the 1.414 value of 2885 VDC, however
reading through the handbook, I seem to be reading I'll get 0.90 the output
voltage.
thanks,
Paul
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