________________________________________
From: amps-bounces@contesting.com [amps-bounces@contesting.com] On Behalf Of
K9FFK [k9ffk@comcast.net]
Sent: Saturday, August 27, 2011 8:00 PM
To: amps@contesting.com
Subject: Re: [Amps] Skin depth: silver plating of tank circuit coil feasible
with
Bill:
I believe you are trying to say the resistance is related to the
cross-sectional area of the conducting material.
Resistance is directly proportional to the resistivity.
(short, fat conductor have lower resistance than long, skinny ones.)
R = rho*L/A
rho = resistivity, L = conductor length, A = cross-sectional area.
Dick K9FFK
On 10/6/2010 9:49 AM, Bill Fuqua wrote:
> The resistance will be the square root of the resistivity of the
> conductor.
> So if the resistivity increases by a factor of 1.1 the resistance will
> increase by
> a factor of 1.05 assuming the thickness or diameter of the conductor is
> much greater
> than the skin depth.
> This is easy to see since the skin depth is directly proportional to
> the square root of
> resistivity.
>
> 73
> Bill wa4lav
>
>
...snip...
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