For those of us simpletons on here, the power ratio formula was noted
because 80W is 0.969100130080564 dB down from 100W.
Don Jones
Arlington, WA
-----Original Message-----
From: Dr. Gerald N. Johnson [mailto:geraldj@weather.net]
Sent: Saturday, April 02, 2011 5:34 PM
To: tentec@contesting.com
Subject: Re: [TenTec] eagle
On 4/2/2011 6:21 PM, Don Jones wrote:
> Power dB = 10LOG*(P1/P2).
That's fine formula for gain and loss based on power ratios, but not a
great benefit in figuring power to a dummy load with a voltmeter. And
what you use as a indicator for the dummy load affects the way you
compute power. For DC its P = E * E / R. For a half wave peak reading
meter (and pure sinewave) its P = 0.5 * Ep * Ep / R. For a peak to
reading like get on the oscilloscope its E = Epp / 2.828427 where
2.828427 is the square root of 8.00000, then apply P = E * E / R. Or P =
Epp * Epp / ( 8 * R)
73, Jerry, K0CQ
>
> Question #1, do you have a calibrated volt meter? Might be useful to check
your input voltage.
> Question #2, is your "50 ohm load" calibrated?
> Question #3, I am not familiar with the Motorola Comm Analyzer... Is it
rated for HF freq's? It is my impression that the Motorola stuff is mostly
VHF/UHF rated equipment.
Good question on its frequency rating.
Go back to the post from 9JML about his experiences comparing final
tuning test bench results with QC at a Motorola factory building two way
radios. He fought differences with "calibrated" equipment all the time.
> Peace,
>
> Don Jones ko7i
> Arlington, WA
>
>
> -----Original Message-----
> From: Mike Bryce [mailto:prosolar@sssnet.com]
> Sent: Friday, April 01, 2011 6:37 PM
> To: Discussion of Ten-Tec Equipment
> Subject: Re: [TenTec] eagle
>
> I have access to a very expensive motorla comm analyzer. $50k, calibrated
to traceable standards.
>
> My personal coaxial dynamic watt meter and if course a 50 ohm dummy load.
>
> So, I am not using an old radio shack CB watt meter, but calibrated RF
test equipment.
>
> Mike
>
> Sent from my iPhone
>
>
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