Here is some differnt info.
http://www.amphenolrf.com/products/typen.asp?N=0&sid=48B3478041F8E17F
-------------- Original message --------------
From: Steve Hunt <steve@karinya.net>
> Joe,
>
> Sorry to "nit pick", but if your formula is correct and the constant is
> 0.5, shouldn't the loss be 0.57dB? It makes a big difference if you have
> several connectors in the chain.
>
> 73,
> Steve G3TXQ
>
>
> Joe Reisert, W1JR wrote:
> > Hi Manius,
> >
> > The insertion loss of a good N connector is equal to the square root
> > of F (in GHz) times a constant (K).
> >
> > The constant for a single N connector is 0.5. Therefore, at 23 CM
> > (1.3 GHz) the loss is approximately .057 dB so you can add up the
> > losses based on your situation.
> >
> > 73,
> >
> > Joe, W1JR
> >
> >
> >
>
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