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Re: [TowerTalk] FW: Vertical Dipoles

To: "towertalk@contesting.com" <towertalk@contesting.com>
Subject: Re: [TowerTalk] FW: Vertical Dipoles
From: "David J. Sourdis" <hk1kxa@hotmail.com>
Date: Wed, 18 Nov 2009 16:35:41 -0500
List-post: <towertalk@contesting.com">mailto:towertalk@contesting.com>
Hallo, Peter,

You are supposed to have the same Rrad if the amps-degrees area are the same.
It should be around 36 ohms like a lossless 90º monopole.

If you check on N6LF-Rudy's article, Table 1 shows that for a 40' vertical 
portion of HVD , Rrad is 33 ohms.

One third of a dipole at 3.510 kHz is 44', extrapolating from the 40' value on 
the table I would say Rrad should get pretty close to 36 ohms, like a 90º 
monopole with zero ground losses.

73


David  
HK1KXA
EC5KXA




> From: df3kv@t-online.de
> To: towertalk@contesting.com
> Date: Wed, 18 Nov 2009 20:06:51 +0100
> Subject: Re: [TowerTalk] FW:  Vertical Dipoles
> 
> If so it does not help much as you still loose on efficiency with a
> shortened radiator
> 
> 73
> Peter
> 
> -----Original Message-----
> 
> If I use a HVD thas has a vertical section 60º and the rest is end loading,
> capacitive, coil, etc, has the same current area as a full sized quarter
> wave monopole.
> 
> 
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