I have several replies already and I understand there are issues
with using the ALC input as proposed. I am scratching that idea.
One responder gave me what looks like the solution. I didn't want to
buy another high power attenuator due to cost and non-existent
budget, but it looks like I don't have to.
I have a 250 watt, 50 ohm flange mount RF resistor. It looks like
the shunt elements in a 40 dB attenuator are so close to 50 ohms
that I can use this on the input side of a home made power
attenuator. Perfect! A zero cost solution (that I should have though
of myself). I just need to do some math to make sure dissipation in
the series element is as low as I think (so that I don't under-build
the thing).
Thanks everyone.
Onward...
73,
Paul
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