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1. [AMPS] 8877 Grid Dissipation (score: 1): Author: philk5pc@connect.net (Phil Clements); Date: Fri, 08 Aug 1997 00:28:12 -0500; The total grid dissipation on a properly loaded 8877 amp running at 4000 volts and loaded to 800 ma plate current is 8.2 watts. Whether the maximum grid dissipation is 20 or 25 watts is not near as i; /archives//html/Amps/1997-08/msg00068.html (8,425 bytes)
2. [AMPS] 8877 Grid Dissipation (score: 1): Author: pgerba@crl.com (Peter Gerba); Date: Thu, 7 Aug 1997 23:16:37 -0700 (PDT); Yep, your right about the 8.2 ! I've found the folks at Eimac, past and present, very helpfull to the Amateur builder. After all Eimac's founders were Amateur builders. I may be wrong, but I think th; /archives//html/Amps/1997-08/msg00071.html (8,905 bytes)
3. [AMPS] 8877 Grid Dissipation (score: 1): Author: w8jitom@postoffice.worldnet.att.net (w8jitom@postoffice.worldnet.att.net); Date: Fri, 8 Aug 1997 10:38:13 +0000; To: <amps@contesting.com> Amen. Since the waveform is complex the grid dissipation can only be found by knowing the time integrated grid to cathode voltage and current over the whole RF cycle, but i; /archives//html/Amps/1997-08/msg00076.html (8,862 bytes)
4. [AMPS] 8877 Grid Dissipation (score: 1): Author: measures@vc.net (Rich Measures); Date: Sun, 10 Aug 97 06:31:32 -0800; Where does the figure of 8.2W come from, Phil? How much grid current equates to 8.2W of grid dissipation? Rich-- R. L. Measures, 805-386-3734, AG6K -- FAQ on WWW: http://www.contesting.com/ampfaq.ht; /archives//html/Amps/1997-08/msg00086.html (7,931 bytes)
5. [AMPS] 8877 Grid Dissipation (score: 1): Author: philk5pc@connect.net (Phil Clements); Date: Mon, 11 Aug 1997 00:35:57 -0500; 55 ma per tube. The tube dissipates 8.2 watts only when the amp is properly loaded and the grid current is 55 ma per tube. (((73))) Phil, K5PC -- FAQ on WWW: http://www.contesting.com/ampfaq.html Sub; /archives//html/Amps/1997-08/msg00098.html (8,097 bytes)
6. [AMPS] 8877 Grid Dissipation (score: 1): Author: measures@vc.net (Rich Measures); Date: Mon, 11 Aug 97 05:23:21 -0800; ... 55mA divided into 8.2 watts equals 149V rms. Since the grid/cathode driving potential for an 8877 is around 50V rms, where does the extra 99V rms come from, Phil? Rich-- R. L. Measures, 805-386-; /archives//html/Amps/1997-08/msg00102.html (8,025 bytes)
7. [AMPS] 8877 Grid Dissipation (score: 1): Author: philk5pc@connect.net (Phil Clements); Date: Mon, 11 Aug 1997 08:31:30 -0500; The 55 ma is only the DC component of the total grid current. This allows the use of a simple DC amp meter to sample the TOTAL complex AC, DC, and RF currents flowing in the grid. By following the Ip; /archives//html/Amps/1997-08/msg00105.html (9,085 bytes)
8. [AMPS] 8877 Grid Dissipation (score: 1): Author: measures@vc.net (Rich Measures); Date: Tue, 12 Aug 97 04:42:16 -0800; At 4000V and 250MHz, the normal AC current in the 8877's grid is 40A rms. At 4000V and 1.9MHz/160m, the normal AC grid current is 0.3A. I don't see how a simple DC current meter can tell the differe; /archives//html/Amps/1997-08/msg00116.html (9,632 bytes)
9. [AMPS] 8877 Grid Dissipation (score: 1): Author: philk5pc@connect.net (Phil Clements); Date: Tue, 12 Aug 1997 09:49:05 -0500; Please go to www.eimac.com/c&f.htm and read what it says. Too much for me to retype. At a constant current, Ep and Eg vary with time. By plotting along the chart with the operating values we are inte; /archives//html/Amps/1997-08/msg00118.html (8,929 bytes)
10. [AMPS] 8877 Grid Dissipation (score: 1): Author: measures@vc.net (Rich Measures); Date: Tue, 12 Aug 97 08:17:08 -0800; I went there, Phil. Section 3.9, 'Protection' is not there, nor is anything beyond Section 3.2.. Rich-- R. L. Measures, 805-386-3734, AG6K -- FAQ on WWW: http://www.contesting.com/ampfaq.html Submis; /archives//html/Amps/1997-08/msg00119.html (8,040 bytes)
11. [AMPS] 8877 Grid Dissipation (score: 1): Author: w8jitom@postoffice.worldnet.att.net (w8jitom@postoffice.worldnet.att.net); Date: Tue, 12 Aug 1997 14:32:56 +0000; Rich, You claim the loss is I^2 R loss. Resistance is easy to define, even if it has a slope with frequency due to skin effect. If the loss causing heat was I^2 R loss, Eimac COULD publish a current; /archives//html/Amps/1997-08/msg00121.html (10,464 bytes)

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