If what you say is true then no resonant circuit has Q. In series resonance Q= Xc/R or you can use inductive reactance. they are equal at resonance. In parallel Q=R/Xc 73 Bill wa4lav ________________
Actually a match is dertermined by the ratio of the antenna Z to the tranzmission line Z. The generater Z has nothing to do with it. At least that is what I remember. So all these amp specs are irrel
But there is no transmission line. So does the tube output, coupling cap, or antenna become part of the transmission line? But first to address the issue of Standing waves on the antenna: my old engi
ORIGINAL MESSAGE: REPLY: In this case, there is no transmission line and no matching network (pi-net), so the generator Z is important. In a normal amp, the pi-net transforms the tube's plate load re
Do w even care if it has a flywheel effect? We really don't care what the wave form is, we don't care about IM, or cleanliness, and we don't care about harmonics so who cares if the whole wave form i
ORIGINAL MESSAGE: REPLY: In this case, we are dealing with an end-fed half wave vertical, which has a feedpoint impedance of several thousand ohms, essentially the same as the tube's plate load imped
ORIGINAL MESSAGE: REPLY: Point taken in the case of the CB idiots. Field strength trumps everything. Please excuse me for thinking like a ham. :-) 73, Bill W6WRT _____________________________________
Not quite. It's true the formula is either X/R or R/X and at resonance Xc and Xl are equal. But the formula says to use EITHER Xc or Xl, not both which would be zero at resonance. 73 Roger (K8RI) ___
Sorry, I clicked on the wrong email. I was responding to Gerald's (K5GW) email where he was in error about resonance and Q. Also, most of us are familiar with R,X and Q and also Bandwidth, Center Fre
Bill, I think you missed part of the discussion:we were not talking about tuned circuits. We were talking about an amplifier with no tank circuit being coupled directly (no transmission line) to an a
ORIGINAL MESSAGE: REPLY: If a parallel resonant circuit has infinite reactance, how does any energy get into it in the first place? Infinite reactance = zero current flow. 73, Bill W6WRT ____________
I was taught a resonant antenna is a tank circuit, antennas usually have some figure of "Q" over 1 and if some of it's capacitance is contributed by the plate to ground of a power tube I don't see h
ORIGINAL MESSAGE: REPLY: Sounds reasonable. 73, Bill W6WRT _______________________________________________ Amps mailing list Amps@contesting.com http://lists.contesting.com/mailman/listinfo/amps