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1. [Amps] Re: AMPS Link coupling (score: 1): Author: R.Measures <r@somis.org>; Date: Sun, 9 Jan 2005 10:07:23 -0800; G3RZP@aol.com wrote The trouble with a direct ground on a balanced feedline is increased risk of sudden discharge -- as in "big-bang".? To reduce this risk, slowly bleed down the static charge with?; /archives//html/Amps/2005-01/msg00149.html (9,597 bytes)
2. Re: [Amps] Re: AMPS Link coupling (score: 1): Author: G3rzp@aol.com; Date: Sun, 9 Jan 2005 13:29:50 EST; There is no antenna matching network that has a lower Q than an L-network. This is not correct. A parallel tuned circuit with a coupling link, loaded by a high impedance antenna can have its LC ratio; /archives//html/Amps/2005-01/msg00150.html (7,334 bytes)
3. Re: [Amps] Re: AMPS Link coupling (score: 1): Author: Tomm Aldridge <KD7QAE@ARRL.NET>; Date: Sun, 09 Jan 2005 19:55:02 +0000; My Balanced-Balanced Tuner (thanks Rich!) is in a wood box w/ cool (free surplus) plexiglass front and back panels. Have not burned myself once! Of course, there are thos big binding posts on the fro; /archives//html/Amps/2005-01/msg00155.html (8,485 bytes)
4. Re: [Amps] Re: AMPS Link coupling (score: 1): Author: "Ian White, G3SEK" <G3SEK@ifwtech.co.uk>; Date: Sun, 9 Jan 2005 23:03:43 +0000; This is not correct. A parallel tuned circuit with a coupling link, loaded by a high impedance antenna can have its LC ratio determined such as to control the value of Q. It is possible that self cap; /archives//html/Amps/2005-01/msg00160.html (8,189 bytes)
5. Re: [Amps] Re: AMPS Link coupling (score: 1): Author: "Steve Thompson" <g8gsq@ic24.net>; Date: Mon, 10 Jan 2005 08:37:21 -0000; Sketching it on a Smith chart, a quarter wave transmission line transformer follows a locus with a lower peak Ql. Does that count, even if it's of limited practical use? Steve _______________________; /archives//html/Amps/2005-01/msg00168.html (8,598 bytes)
6. Re: [Amps] Re: AMPS Link coupling (score: 1): Author: G3rzp@aol.com; Date: Mon, 10 Jan 2005 03:56:07 EST; The minimum possible *loaded* Q that is required to transform between two resistances R2>R1, using any possible circuit, is sqrt(R2/R1 -1). Perfectly true if you don't use a transformer. The link cou; /archives//html/Amps/2005-01/msg00169.html (7,432 bytes)

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