- 1. [TowerTalk] Re: Tower Faraday shield? (score: 1)
- Author: olinger@bellsouth.net (Guy Olinger, K2AV)
- Date: Sun Jun 1 14:42:03 2003
- Since so much of lightning is pulse related, and I don't have a verifiable analytical device to measure and take that into account, I can't really say that it does or doesn't work and why. However, i
- /archives//html/Towertalk/2003-06/msg00007.html (10,976 bytes)
- 2. [TowerTalk] Re: Tower Faraday shield? (score: 1)
- Author: norsan@bright.net (Norman Hockler)
- Date: Sun Jun 1 15:10:30 2003
- To be a Faraday shield the enclosure must have no holes larger than a wave guide at cuttoff to the highest frequency you want protection from. By this definition a tower is not much of a Faraday shie
- /archives//html/Towertalk/2003-06/msg00009.html (7,498 bytes)
- 3. [TowerTalk] Re: Tower Faraday shield? (score: 1)
- Author: jimlux@earthlink.net (Jim Lux)
- Date: Sun Jun 1 17:21:42 2003
- bear in mind also that the tower is made of steel covered with zinc, hardly the conductivity of copper. Lower conductivity means greater skin depth, and skin depth is very related to the amount of s
- /archives//html/Towertalk/2003-06/msg00014.html (8,312 bytes)
- 4. [TowerTalk] Re: Tower Faraday shield? (score: 1)
- Author: K7LXC@aol.com (K7LXC@aol.com)
- Date: Sun Jun 1 20:02:21 2003
- Then what's the hole size we're talking about at 14 mHz? Cheers, Steve K7LXC
- /archives//html/Towertalk/2003-06/msg00019.html (6,837 bytes)
- 5. [TowerTalk] Re: Tower Faraday shield? (score: 1)
- Author: jimlux@earthlink.net (Jim Lux)
- Date: Mon Jun 2 00:35:06 2003
- Ballpark figure for "significant" hole sizes is perimeter >1/2 wavelength, so, at 14 MHz, a 10 m perimeter hole, or about 10 ft in diameter... The hole acts as a dipole antenna (Babinet's theorem say
- /archives//html/Towertalk/2003-06/msg00030.html (8,773 bytes)
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