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Total 45 documents matching your query.

1. [AMPS] Conjugate Matching and Efficiency (score: 1): Author: na9d@speakeasy.net (Jon Ogden); Date: Thu, 17 May 2001 00:28:56 -0500; After noodling all of the ideas tossed back and forth regarding conjugate matching and efficiency, I have come up with the following simplifications to try to clarify the idea. If there are any error; /archives//html/Amps/2001-05/msg00325.html (12,076 bytes)
2. [AMPS] Conjugate Matching and Efficiency (score: 1): Author: billydeanward@hotmail.com (Billy Ward); Date: Thu, 17 May 2001 16:01:51 -0000; I don't have the time today to re-read and study your statements but I think that I am following you. However, just a quick thought. Suppose the amp is 100% efficient. (We all know that it cannot be!; /archives//html/Amps/2001-05/msg00335.html (15,041 bytes)
3. [AMPS] Conjugate Matching and Efficiency (score: 1): Author: na9d@speakeasy.net (Jon Ogden); Date: Thu, 24 May 2001 07:34:32 -0500; Hi Billy, I've been trying long and hard to come up with a "scientific" answer to your point and have been consulting with others as well as noodling it around in my head. Let's see how this works. I; /archives//html/Amps/2001-05/msg00402.html (14,751 bytes)
4. [AMPS] Conjugate Matching and Efficiency (score: 1): Author: billydeanward@hotmail.com (Billy Ward); Date: Thu, 24 May 2001 15:09:04 -0000; Hi John, I just had to skim your thesis. I am at the library and only have 30 minutes time to use the internet. My phone is not in yet at the shop. I see your point but I will read the thesis and stu; /archives//html/Amps/2001-05/msg00407.html (17,535 bytes)
5. [AMPS] Conjugate Matching and Efficiency (score: 1): Author: bogus@does.not.exist.com (Jon Ogden); Date: Thu, 24 May 2001 13:35 -0700; To: <amps@contesting.com> I fail to understand your point. What do you mean by the 3 dB down point? If you mean the 3 dB points in a filter (which is essentially what a matching network is), that is; /archives//html/Amps/2001-05/msg00412.html (13,682 bytes)
6. [AMPS] Conjugate Matching and Efficiency (score: 1): Author: g8gsq@qsl.net (Steve Thompson); Date: Fri, 25 May 2001 14:47:30 +0100; snip If you mean the 3 dB points in a filter (which is essentially what a matching network is), that is something completely different. I assume that's what you mean so I'll address that. bandwidth.; /archives//html/Amps/2001-05/msg00429.html (9,595 bytes)
7. [AMPS] Conjugate Matching and Efficiency (score: 1): Author: billydeanward@hotmail.com (Billy Ward); Date: Fri, 25 May 2001 16:09:10 -0000; Greetings Jon, Again, I must admit that I only have time to skim. There are folks waiting to use this computer and I have bout 9 minutes. JOHN: At the 3 dB points, half the power that is transmitted; /archives//html/Amps/2001-05/msg00432.html (11,139 bytes)
8. [AMPS] Conjugate Matching and Efficiency (score: 1): Author: billydeanward@hotmail.com (Billy Ward); Date: Fri, 25 May 2001 17:17:29 -0000; By the way Jon, I forgot to mention in the last letter that when I was originally talking about the 3db down point and the calculations, I was not thinking straight and I was confusing the voltage di; /archives//html/Amps/2001-05/msg00433.html (13,370 bytes)
9. [AMPS] Conjugate Matching and Efficiency (score: 1): Author: billydeanward@hotmail.com (Billy Ward); Date: Fri, 25 May 2001 17:30:28 -0000; STEVE: For power to be reflected, doesn't the source have to be a transmission line? A series C can reduce the power delivered to a load just by adding reactance and increasing the overall impedance; /archives//html/Amps/2001-05/msg00434.html (11,862 bytes)
10. [AMPS] Conjugate Matching and Efficiency (score: 1): Author: na9d@speakeasy.net (Jon Ogden); Date: Fri, 25 May 2001 18:31:37 -0500; What do you mean "doesn't the source have to be a transmission line?" A series C can indeed do what you say. However, a true series C does not dissipate energy but stores it. I was speaking in terms; /archives//html/Amps/2001-05/msg00435.html (9,933 bytes)
11. [AMPS] Conjugate Matching and Efficiency (score: 1): Author: W8JI@contesting.com (Tom Rauch); Date: Fri, 25 May 2001 22:37:42 -0400; I haven't been following this....but.... The only possible heat source in a reactance is due to loss resistance. In a good quality capacitor, loss is almost zero. Small mica caps can be as low as 500; /archives//html/Amps/2001-05/msg00436.html (11,153 bytes)
12. [AMPS] Conjugate Matching and Efficiency (score: 1): Author: g8gsq@qsl.net (Steve Thompson); Date: Sat, 26 May 2001 10:08:10 +0100; it. As Tom said, a perfect capacitor would not heat up. A real capacitor has some resistance, and it's there that the heat is generated. The amount of resistance varies according to the dielectric ma; /archives//html/Amps/2001-05/msg00440.html (10,124 bytes)
13. [AMPS] Conjugate Matching and Efficiency (score: 1): Author: g8gsq@qsl.net (Steve Thompson); Date: Sat, 26 May 2001 10:20:16 +0100; --Original Message-- From: Jon Ogden <na9d@speakeasy.net> To: Steve Thompson <g8gsq@qsl.net>; amps@contesting.com <amps@contesting.com> To: <amps@contesting.com> Date: 26 May 2001 00:31 Subject: Re:; /archives//html/Amps/2001-05/msg00441.html (10,492 bytes)
14. [AMPS] Conjugate Matching and Efficiency (score: 1): Author: na9d@speakeasy.net (Jon Ogden); Date: Sat, 26 May 2001 08:22:43 -0500; Billy, Take a look at a filter plot of both S21 and S11. I can send some to you if you need any since I sell them. At frequencies outside the passband of the filter, S11 is high. A filter is a REFLEC; /archives//html/Amps/2001-05/msg00443.html (14,380 bytes)
15. [AMPS] Conjugate Matching and Efficiency (score: 1): Author: na9d@speakeasy.net (Jon Ogden); Date: Sat, 26 May 2001 08:26:34 -0500; A CAPACITOR IS NOT A DISSIPATIVE DEVICE!! Period. Any heat generated in the device is caused by losses that are real world and are the electrical equivalent of friction. There is some parasitic resis; /archives//html/Amps/2001-05/msg00444.html (10,338 bytes)
16. [AMPS] Conjugate Matching and Efficiency (score: 1): Author: na9d@speakeasy.net (Jon Ogden); Date: Sat, 26 May 2001 08:34:40 -0500; S-Parameters can be used and applied to any n port device. If our box is a transmitter, it will only have one port. Therefore, the only S parameter we can measure is S11. You don't have to have a tra; /archives//html/Amps/2001-05/msg00445.html (11,100 bytes)
17. [AMPS] Conjugate Matching and Efficiency (score: 1): Author: jeff@wa1hco.mv.com (jeff millar); Date: Sat, 26 May 2001 10:35:22 -0400; Several posts have referred to reflected power from a mismatched filter. People have reasoned, "If the output is 3 dB down, then the power has to go somewhere". But, it's also reasonable to consider; /archives//html/Amps/2001-05/msg00446.html (9,563 bytes)
18. [AMPS] Conjugate Matching and Efficiency (score: 1): Author: 2@vc.net (2); Date: Sat, 26 May 2001 09:31:51 -0700; ? ... good points. cheers, Jeff, - R. L. Measures, 805.386.3734, www.vcnet.com/measures. end -- FAQ on WWW: http://www.contesting.com/FAQ/amps Submissions: amps@contesting.com Administrative request; /archives//html/Amps/2001-05/msg00448.html (9,517 bytes)
19. [AMPS] Conjugate Matching and Efficiency (score: 1): Author: Michael Tope" <W4EF@dellroy.com (Michael Tope); Date: Sat, 26 May 2001 06:38:46 -0700; In the steady state, the transmission line will be nothing more than an impedance transformer. Depending on the load impedance and the Zo of the line, and the length of the line, it will transform th; /archives//html/Amps/2001-05/msg00449.html (12,282 bytes)
20. [AMPS] Conjugate Matching and Efficiency (score: 1): Author: W8JI@contesting.com (Tom Rauch); Date: Sat, 26 May 2001 14:14:27 -0400; That certainly makes sense. The source does not have to "produce" the RF power when the load isn't matched. The sources we use are energy converters that convert a dc source to RF with a time-varyin; /archives//html/Amps/2001-05/msg00450.html (10,208 bytes)

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