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1. [AMPS] Re: Power Handling of Resistors (score: 1): Author: Carl Clawson" <ws7l@arrl.net (Carl Clawson); Date: Thu, 9 Mar 2000 19:36:34 -0800; not It takes about 500 J to melt a gram of brass from room temperature. I think 256 would be enough to seriously damage a band switch. The unresolved problem isn't the available energy, it's how it; /archives//html/Amps/2000-03/msg00514.html (8,166 bytes)
2. [AMPS] Re: Power Handling of Resistors (score: 1): Author: 2@vc.net (measures); Date: Thu, 9 Mar 2000 20:20:17 -0700; Good news, Carl. The unresolved problem has already been solved by the modest Mr. Rauch. The energy gets to the switch because C-tune has a VHF resonance slightly above the parasitic freq.. For exam; /archives//html/Amps/2000-03/msg00516.html (8,553 bytes)
3. [AMPS] Re: Power Handling of Resistors (score: 1): Author: jono@enteract.com (Jon Ogden); Date: Thu, 09 Mar 2000 22:44:49 -0600; Let's do the math: A Joule is 1 Watt-second. Multiply watts times seconds. If I am transmitting at 1500 Watts for 10 seconds, the total energy passing through the switch is 15,000 joules. So if I can; /archives//html/Amps/2000-03/msg00517.html (8,946 bytes)
4. [AMPS] Re: Power Handling of Resistors (score: 1): Author: Carl Clawson" <ws7l@arrl.net (Carl Clawson); Date: Thu, 9 Mar 2000 21:36:51 -0800; through (or Passing 1500 watts through closed terminals of the band switch doesn't dissipate 1500 watts in the switch or it would shortly be toast. We hope the 1500 watts makes it to the antenna. Ac; /archives//html/Amps/2000-03/msg00521.html (10,285 bytes)
5. [AMPS] Re: Power Handling of Resistors (score: 1): Author: W4EF@pacbell.net (Michael Tope); Date: Thu, 09 Mar 2000 22:04:03 -0800; Jon, In your example below I think you are confusing transmission of energy with conversion of energy. In the case of a properly operating amplifier which is generating 1500 watts of output power, th; /archives//html/Amps/2000-03/msg00523.html (11,754 bytes)
6. [AMPS] Re: Power Handling of Resistors (score: 1): Author: jono@enteract.com (Jon Ogden); Date: Fri, 10 Mar 2000 00:15:35 -0600; OK. You're correct. Understand now what you are saying. Certainly you are correct when it comes to how much power one could actually dissipate in the switch. No doubt about that! Thanks for clearing; /archives//html/Amps/2000-03/msg00524.html (9,055 bytes)
7. [AMPS] Re: Power Handling of Resistors (score: 1): Author: jono@enteract.com (Jon Ogden); Date: Fri, 10 Mar 2000 00:22:06 -0600; You are correct. Carl straightened me out. The words "to" and "through" mean very different things even though the power has to go "to" the bandswitch before it goes "to" the load. Agreed. And switch; /archives//html/Amps/2000-03/msg00525.html (11,035 bytes)
8. [AMPS] Re: Power Handling of Resistors (score: 1): Author: itr@nanoteq.co.za (Ian Roberts); Date: Fri, 10 Mar 2000 08:32:56 +0200; An arc is energy applied to a POINT target, in this case the thin contacts of a bandswitch in the presence of oxygen. We aren't talking about melting down metal ingots here. -- FAQ on WWW: http://www; /archives//html/Amps/2000-03/msg00527.html (8,368 bytes)
9. [AMPS] Re: Power Handling of Resistors (score: 1): Author: wb8jkr@juno.com (Mark S Graalman); Date: Fri, 10 Mar 2000 05:46:54 -0500; Jon, I THINK we may be getting a little off the path here. First, 1500 watts through something isn't the same as 1500 watts TO something. You could run 1500 watts of power through a 1 foot length of; /archives//html/Amps/2000-03/msg00531.html (8,635 bytes)

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