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21. [AMPS] Diodes (score: 1): Author: 2@vc.net (measures); Date: Tue, 22 Feb 2000 16:32:23 -0700; hardly - page 11-9 of the Handbook: "In fact shunt resistors produce a low impedance source of damaging current to any diode that may have reached avalanche potential." It seems a bit curious that y; /archives//html/Amps/2000-02/msg00516.html (11,966 bytes)
22. [AMPS] Diodes (score: 1): Author: G3SEK@ifwtech.demon.co.uk (Ian White, G3SEK); Date: Wed, 23 Feb 2000 08:01:23 +0000; Erm, don't you mean "amen"? Wake up, Rich - I was agreeing with you! I rest my case. 73 from Ian G3SEK Editor, 'The VHF/UHF DX Book' 'In Practice' columnist for RadCom (RSGB) http://www.ifwtech.demon; /archives//html/Amps/2000-02/msg00518.html (9,471 bytes)
23. [AMPS] Diodes (score: 1): Author: Peter_Chadwick@mitel.com (Peter Chadwick); Date: Wed, 23 Feb 2000 09:44:17 -0000; alone AC, the Which assumption? Your assumption is that the voltage will divide unequally. However, if the diodes have equal capacities, then the 250 volts will divide to give 125 volts across each d; /archives//html/Amps/2000-02/msg00519.html (10,020 bytes)
24. [AMPS] Diodes (score: 1): Author: 2@vc.net (measures); Date: Wed, 23 Feb 2000 07:17:21 -0700; That the capacitances are substantially different. Without equalization, the 250v reverse surge happily divides unequally. Approx. 101v is dropped acrosss the 101v diode and approx. 149v is dropped; /archives//html/Amps/2000-02/msg00521.html (11,319 bytes)
25. [AMPS] Diodes (score: 1): Author: 2@vc.net (measures); Date: Wed, 23 Feb 2000 07:17:25 -0700; no. My position is that "not necessary" is not The compelling reason to avoid equalization. Your position appears to be 'not necessary. The p.11-9 Handbook statement goes one step beyond saying not; /archives//html/Amps/2000-02/msg00522.html (9,803 bytes)
26. [AMPS] Diodes (score: 1): Author: Peter_Chadwick@mitel.com (Peter Chadwick); Date: Wed, 23 Feb 2000 15:25:17 -0000; Not if the diode capacities are equal. Two equal diode capacities will attempt to split the voltage equally. The probability is that they aren't equal, though. Frequency has nothing to do with it, si; /archives//html/Amps/2000-02/msg00523.html (8,904 bytes)
27. [AMPS] Diodes (score: 1): Author: 2@vc.net (measures); Date: Wed, 23 Feb 2000 08:51:37 -0700; True, however the typical 5ua reverse current ability charges the tiny capacitances with aplomb. ?? to the Crybabies are still awake: -- is this boring or what? Remember the good times when you coul; /archives//html/Amps/2000-02/msg00525.html (9,167 bytes)
28. [AMPS] Diodes (score: 1): Author: 2@vc.net (measures); Date: Wed, 23 Feb 2000 08:51:35 -0700; the resistance of the equalizers is not a factor? A safe wager. . . The 10k-ohm "equalizer" resistances seem to be in the driver's seat. cheers, Peter -- FAQ on WWW: http://www.contesting.com/ampsfa; /archives//html/Amps/2000-02/msg00526.html (8,997 bytes)
29. [AMPS] Diodes (score: 1): Author: Peter_Chadwick@mitel.com (Peter Chadwick); Date: Wed, 23 Feb 2000 17:11:13 -0000; tiny Now, where does the 5uA current come from? Only when the diode goes into reverse leakage, i.e. when the reverse voltage is exceeded. So it appears that to get your distribution, the 5uA leakage; /archives//html/Amps/2000-02/msg00527.html (9,860 bytes)
30. [AMPS] Diodes (score: 1): Author: G3SEK@ifwtech.demon.co.uk (Ian White, G3SEK); Date: Wed, 23 Feb 2000 21:19:52 +0000; Ah, I see... sorry, that was a bit too cryptic for me. AND IF there are too few diodes in the string (a design fault) AND IF (in spite of the equalization of inverse voltages) one diode is still push; /archives//html/Amps/2000-02/msg00528.html (10,666 bytes)
31. [AMPS] Diodes (score: 1): Author: 2@vc.net (measures); Date: Wed, 23 Feb 2000 14:30:20 -0700; No one said there was 5uA. I said that the ability was 5uA. My guess is that, at 50Hz, no more than 1uA is needed to charge the tiny capacitances. 'Is approached' would be a bit closer. The reverse; /archives//html/Amps/2000-02/msg00531.html (11,426 bytes)
32. [AMPS] Diodes (score: 1): Author: 2@vc.net (measures); Date: Wed, 23 Feb 2000 15:09:49 -0700; ...... In the example given the total piv was 291v. The surge was 250v. No problem occurred without ''equalization''. . alas Indeed, Ian. And do you measure the avalance potential of each unit? If y; /archives//html/Amps/2000-02/msg00532.html (9,623 bytes)
33. [AMPS] Diodes (score: 1): Author: Peter_Chadwick@mitel.com (Peter Chadwick); Date: Thu, 24 Feb 2000 09:00:46 -0000; When the reverse knee is approached, the diode starts to conduct. If the diode in series with it isn't conducting, how does that happen? Seems there are some people out there awake Rich, even if th i; /archives//html/Amps/2000-02/msg00538.html (8,527 bytes)
34. [AMPS] Diodes (score: 1): Author: G3SEK@ifwtech.demon.co.uk (Ian White, G3SEK); Date: Thu, 24 Feb 2000 09:15:32 +0000; No, because I don't have the capability to measure it at the actual junction temperature it will reach when operating at full load. Instead I buy quality parts and rely on uniformity from mass-produc; /archives//html/Amps/2000-02/msg00540.html (9,534 bytes)
35. [AMPS] Diodes (score: 1): Author: Peter_Chadwick@mitel.com (Peter Chadwick); Date: Thu, 24 Feb 2000 10:08:38 -0000; If you knew some of the horror stories about semi-conductor processing, you wouldn't be quite so sure about the uniformity! Seriously, the variation in parameters of devices from opposite sides of a; /archives//html/Amps/2000-02/msg00541.html (8,423 bytes)
36. [AMPS] Diodes (score: 1): Author: 2@vc.net (measures); Date: Thu, 24 Feb 2000 05:03:04 -0700; Hair dryers are not costly. Good point. The unequalized, ancient, non-avalanche type diodes in the SB-220's anode supply have a safety factor of c. 35%, yet they do pretty ok. The ''equalizer'' resi; /archives//html/Amps/2000-02/msg00545.html (9,590 bytes)
37. [AMPS] Diodes (score: 1): Author: 2@vc.net (measures); Date: Thu, 24 Feb 2000 05:03:08 -0700; agreed. However, since the 190v diode that is series is quite likely conducting in the low nA range, virtually no current flows in either diode. The total is 250v. Subract 101v for the lesser diode.; /archives//html/Amps/2000-02/msg00547.html (8,434 bytes)
38. SV: [AMPS] Diodes (score: 1): Author: 2@vc.net (measures); Date: Thu, 24 Feb 2000 10:47:07 -0700; Interesting observation and good question. . . The AL-80 and similar SB-1000 do not seem to have enough bypassing on the HV lead for anything below 7MHz operation. . It would have been better to put; /archives//html/Amps/2000-02/msg00554.html (8,051 bytes)
39. [AMPS] Diodes (score: 1): Author: philk5pc@tyler.net (Phil Clements); Date: Fri, 25 Feb 2000 14:50:12 -0600; I just liberated a diode bridge from a radio junk yard. It is by "CKE," whomever that is; Model # CK236. There are 120 diodes in the bridge, made by "GI" Model # GI 8823. The unique thing about the b; /archives//html/Amps/2000-02/msg00578.html (8,116 bytes)
40. [AMPS] Diodes (score: 1): Author: agray@voicenet.com (Alan Gray); Date: Sat, 26 Feb 2000 20:10:32 -0500; Phil Try this web site for info on CKE products: http://www.cke.com/ Alan, W3BV -- FAQ on WWW: http://www.contesting.com/ampsfaq.html Submissions: amps@contesting.com Administrative requests: amps-RE; /archives//html/Amps/2000-02/msg00593.html (9,283 bytes)

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