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41. Re: [Amps] Measuring RF Power (score: 1): Author: David Kirkby <david.kirkby@onetel.net>; Date: Sat, 26 Mar 2005 00:26:43 +0000; Now I think you are wrong to disagree with K4FMX. I don;'t believe a simple multiple of the RMS values of voltage and current gives the rms power. If you have 1V peak across 1 Ohm you have an RMS vol; /archives//html/Amps/2005-03/msg00559.html (12,513 bytes)
42. Re: [Amps] Measuring RF Power (score: 1): Author: David Kirkby <david.kirkby@onetel.net>; Date: Sat, 26 Mar 2005 00:37:49 +0000; PS, the average power of a 1V peak sine wave across 1 Ohms is 1/2 W, as we all know. You can demonstrate mathematically. Just integrate the shape of the power waveform (which is sin^2) over some inte; /archives//html/Amps/2005-03/msg00560.html (10,180 bytes)
43. Re: [Amps] Measuring RF Power (score: 1): Author: R.Measures <r@somis.org>; Date: Fri, 25 Mar 2005 16:51:53 -0800; Does P = I x E? Chortle Richard L. Measures, AG6K, 805.386.3734. www.somis.org _______________________________________________ Amps mailing list Amps@contesting.com http://lists.contesting.com/mailma; /archives//html/Amps/2005-03/msg00561.html (13,050 bytes)
44. Re: [Amps] Measuring RF Power (score: 1): Author: David Kirkby <david.kirkby@onetel.net>; Date: Sat, 26 Mar 2005 01:36:19 +0000; I agree with you Gary (not specifically that its a common misconception), but that RMS power is not the same as average power for a sinusoidal voltage applies to a resistor. For 1V peak voltage and 1; /archives//html/Amps/2005-03/msg00563.html (10,543 bytes)
45. Re: [Amps] Measuring RF Power (score: 1): Author: David Kirkby <david.kirkby@onetel.net>; Date: Sat, 26 Mar 2005 02:12:50 +0000; Rich, You have in the past gone to great lengths to try to back up your views on parasitic oscillations - is it asking too much to ask you to substantiate something as simple as power in a resistor?; /archives//html/Amps/2005-03/msg00564.html (10,616 bytes)
46. Re: [Amps] Measuring RF Power (score: 1): Author: David Kirkby <david.kirkby@onetel.net>; Date: Sat, 26 Mar 2005 02:18:16 +0000; question when nothing is not defined properly. I mean nothing (P, I or E) are defined properly of course. But don't bother defining them for now - substantiate what you are saying. -- Dr. David Kirk; /archives//html/Amps/2005-03/msg00565.html (9,867 bytes)
47. Re: [Amps] Measuring RF Power (score: 1): Author: Tomm Aldridge <KD7QAE@ARRL.NET>; Date: Sat, 26 Mar 2005 02:59:22 +0000; All, Some basic electronics follows. RMS Voltage or Current can be used to calculate power flow from a linear element, such as a resistor or any other impedance not related to the value of the voltag; /archives//html/Amps/2005-03/msg00566.html (11,049 bytes)
48. Re: [Amps] Measuring RF Power (score: 1): Author: R.Measures <r@somis.org>; Date: Sat, 26 Mar 2005 00:33:40 -0800; Bananas Richard L. Measures, AG6K, 805.386.3734. www.somis.org _______________________________________________ Amps mailing list Amps@contesting.com http://lists.contesting.com/mailman/listinfo/amps; /archives//html/Amps/2005-03/msg00569.html (11,567 bytes)
49. Re: [Amps] Measuring RF Power (score: 1): Author: R.Measures <r@somis.org>; Date: Sat, 26 Mar 2005 00:49:12 -0800; What does "nothing is not defined properly" mean? As I understand this matter, for AC, V-peak ^2 / R = P-peak, V-rms^2 / R = P-rms. If the last equation is true, then P-rms = V-rms x I-rms. Richard L; /archives//html/Amps/2005-03/msg00570.html (11,341 bytes)
50. Re: [Amps] Measuring RF Power (score: 1): Author: "Steve Thompson" <g8gsq@ic24.net>; Date: Sat, 26 Mar 2005 09:10:48 -0000; It isn't true. V-rms^2/R = Pmean (or average). Steve _______________________________________________ Amps mailing list Amps@contesting.com http://lists.contesting.com/mailman/listinfo/amps; /archives//html/Amps/2005-03/msg00572.html (9,685 bytes)
51. Re: [Amps] Measuring RF Power (score: 1): Author: R.Measures <r@somis.org>; Date: Sat, 26 Mar 2005 02:39:14 -0800; So what does one find by multiplying V-rms by I-rms? Richard L. Measures, AG6K, 805.386.3734. www.somis.org _______________________________________________ Amps mailing list Amps@contesting.com http:; /archives//html/Amps/2005-03/msg00573.html (10,238 bytes)
52. Re: [Amps] Measuring RF Power (score: 1): Author: "Steve Thompson" <g8gsq@ic24.net>; Date: Sat, 26 Mar 2005 11:05:58 -0000; Pmean (or average). Steve _______________________________________________ Amps mailing list Amps@contesting.com http://lists.contesting.com/mailman/listinfo/amps; /archives//html/Amps/2005-03/msg00574.html (10,078 bytes)
53. Re: [Amps] Measuring RF Power (score: 1): Author: David Kirkby <david.kirkby@onetel.net>; Date: Sat, 26 Mar 2005 12:44:50 +0000; Interpreting the unintentional double-negative correctly, it means everything is defined properly. But I did correct myself when I said in a short post "I mean nothing (P, I or E) are defined properl; /archives//html/Amps/2005-03/msg00575.html (13,061 bytes)
54. Re: [Amps] Measuring RF Power (score: 1): Author: "Will Matney" <craxd1@ezwv.com>; Date: Sat, 26 Mar 2005 09:34:14 -0500; I've been setting back and watching this and hope some aren't confusing rms and average voltage as the same thing. RMS or (root mean square) is calculated as 0.707 X peak voltage. The average voltage; /archives//html/Amps/2005-03/msg00576.html (11,863 bytes)
55. Re: [Amps] Measuring RF Power (score: 1): Author: R.Measures <r@somis.org>; Date: Sat, 26 Mar 2005 06:58:37 -0800; Is that not the heat produced in the R a.k.a. P-rms ? Richard L. Measures, AG6K, 805.386.3734. www.somis.org _______________________________________________ Amps mailing list Amps@contesting.com http; /archives//html/Amps/2005-03/msg00577.html (10,570 bytes)
56. Re: [Amps] Measuring RF Power (score: 1): Author: David Kirkby <david.kirkby@onetel.net>; Date: Sat, 26 Mar 2005 15:45:09 +0000; yes no -- Dr. David Kirkby, G8WRB Please check out http://www.g8wrb.org/ of if you live in Essex http://www.southminster-branch-line.org.uk/ _______________________________________________ Amps maili; /archives//html/Amps/2005-03/msg00578.html (10,732 bytes)
57. Re: [Amps] Measuring RF Power (score: 1): Author: R.Measures <r@somis.org>; Date: Sat, 26 Mar 2005 08:11:44 -0800; ** ___ Richard L. Measures, AG6K, 805.386.3734. www.somis.org _______________________________________________ Amps mailing list Amps@contesting.com http://lists.contesting.com/mailman/listinfo/amps; /archives//html/Amps/2005-03/msg00579.html (10,946 bytes)
58. Re: [Amps] Measuring RF Power (score: 1): Author: "Steve Thompson" <g8gsq@ic24.net>; Date: Sat, 26 Mar 2005 16:12:08 -0000; As David said, yes it's the power, no it's not the rms power. Vrms is the (square)Root of the Mean of the Squares (of the Voltage samples). When you work out Vrms^2 in order to work out the power, yo; /archives//html/Amps/2005-03/msg00580.html (10,900 bytes)
59. Re: [Amps] Measuring RF Power (score: 1): Author: David Kirkby <david.kirkby@onetel.net>; Date: Sat, 26 Mar 2005 17:03:40 +0000; The confusion seems to be more about average power and RMS power. The average voltage of a sine wave is 0. Some of us know that. Some don't seem able to appreciate it. The top of this page http://www; /archives//html/Amps/2005-03/msg00581.html (15,357 bytes)
60. Re: [Amps] Measuring RF Power (score: 1): Author: Dennis12Amplify@aol.com; Date: Sat, 26 Mar 2005 13:51:56 EST; Vrms is the (square)Root of the Mean of the Squares (of the Voltage samples). When you work out Vrms^2 in order to work out the power, you are squaring the squareroot, so the r in rms disappears and; /archives//html/Amps/2005-03/msg00583.html (8,212 bytes)

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