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1. [Amps] RE : Led display problem (score: 1): Author: "hermans" <on4kj@skynet.be>; Date: Tue, 19 Apr 2005 21:08:38 +0100; Hall effect!!.... would you make clear how you would proceed with a hall effect Francis. Jos on4kj De?: amps-bounces@contesting.com [mailto:amps-bounces@contesting.com] De la part de Carcia, Francis; /archives//html/Amps/2005-04/msg00401.html (9,519 bytes)
2. Re: [Amps] RE : Led display problem (score: 1): Author: "Carcia, Francis A HS" <francis.carcia@hs.utc.com>; Date: Tue, 19 Apr 2005 16:15:06 -0400; Hall effect is an active current transformer device so it would be used to measure current. I think digi key sells them. It converts current to volts. The device fits over an insulated wire for high; /archives//html/Amps/2005-04/msg00402.html (9,142 bytes)
3. Re: [Amps] RE : Led display problem (score: 1): Author: Mark Moss <amps@mmoss.org>; Date: Tue, 19 Apr 2005 19:30:52 -0400; I'll fill in a bit more detail here: More specifically, Hall-effect sensors convert magnetic flux density into voltage. I can think of at least two common ways hall-effect sensors are used to measure; /archives//html/Amps/2005-04/msg00405.html (10,734 bytes)
4. Re: [Amps] RE : Led display problem (score: 1): Author: Patrick EGLOFF <pegloff@gmail.com>; Date: Sat, 23 Apr 2005 08:53:56 +0200; Hi All, Thanks for all answers to my request. Nice feedbacks ! I think i found a nice "hamspiritic" list. Abt the utility of bargraphs compared to analog meters, i think that after initial test durin; /archives//html/Amps/2005-04/msg00461.html (9,129 bytes)
5. Re: [Amps] RE : Led display problem (score: 1): Author: Steve Thompson <g8gsq@ic24.net>; Date: Sat, 23 Apr 2005 08:58:28 +0100; I think there are many opto couplers that have enough linearity without feedback to give you 5% or better accuracy and linearity, which is as good as a cheap meter movement. I'm also sure I've seen l; /archives//html/Amps/2005-04/msg00462.html (8,296 bytes)
6. Re: [Amps] RE : Led display problem (score: 1): Author: Karl-Arne Markström <sm0aom@telia.com>; Date: Sat, 23 Apr 2005 10:05:42 +0200; I would recommend "attacking" this problem in two ways. The first is to arrange all current metering so it takes place at the lowest potential point possible referenced to DC and RF ground. In a DC g; /archives//html/Amps/2005-04/msg00463.html (12,293 bytes)

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