I recall an article in RF Design magazine which suggested that the rf current moves away from high resistivity, I think there was some maths supporting the analysis. If the outer surface of a (e.g. c
Are you saying that current takes the path of least resistance? What a great concept! That sure explains why insulation on a conductor works. 73, Gerald K5GW In a message dated 10/4/2010 3:51:01 P.M.
Yes and no appears to be the answer - rf current doesn't take the lowest possible resistance path, it crowds on the outside surface of a conductor. Once there it appears to look for the lowest resist
ORIGINAL MESSAGE: REPLY: An ancient canard. Current takes all paths where resistance (less than infinite) is present, not just the one path of least resistance. 73, Bill W6WRT _______________________
Steve, I was thinking that one of the guys here on the board had done some actual testing on this and found no significant difference at least in the power levels most run. Guys in the NZ 400w class
Author: "Dr. David Kirkby" <david.kirkby@onetel.net>
Date: Tue, 05 Oct 2010 17:29:53 +0100
I can see some logic in that, though I agree with you it's not as simple as current just taking the lowest resistance path. The only analytical equation I've seen for skin depth assumes just two mate
The resistance will be the square root of the resistivity of the conductor. So if the resistivity increases by a factor of 1.1 the resistance will increase by a factor of 1.05 assuming the thickness
Bill: I believe you are trying to say the resistance is related to the cross-sectional area of the conducting material. Resistance is directly proportional to the resistivity. (short, fat conductor h
________________________________________ From: amps-bounces@contesting.com [amps-bounces@contesting.com] On Behalf Of K9FFK [k9ffk@comcast.net] Sent: Saturday, August 27, 2011 8:00 PM To: amps@contes