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1. [TowerTalk] Connector Loss Question (score: 1): Author: "Marinus Willemstijn" <willemma@telkomsa.net>; Date: Sun, 24 Aug 2008 07:36:39 +0200; Sorry if this question do not belong her but I want to know how do you determine connector losses on 23cm? I have the losses for Andrew LD 4-50A but what about the connectors? And if I have to use a; /archives//html/Towertalk/2008-08/msg00472.html (7,222 bytes)
2. Re: [TowerTalk] Connector Loss Question (score: 1): Author: "Joe Reisert, W1JR" <W1JR@arrl.net>; Date: Sun, 24 Aug 2008 18:41:41 -0400; Hi Manius, The insertion loss of a good N connector is equal to the square root of F (in GHz) times a constant (K). The constant for a single N connector is 0.5. Therefore, at 23 CM (1.3 GHz) the los; /archives//html/Towertalk/2008-08/msg00477.html (8,221 bytes)
3. Re: [TowerTalk] Connector Loss Question (score: 1): Author: Steve Hunt <steve@karinya.net>; Date: Tue, 26 Aug 2008 11:50:12 +0100; Joe, Sorry to "nit pick", but if your formula is correct and the constant is 0.5, shouldn't the loss be 0.57dB? It makes a big difference if you have several connectors in the chain. 73, Steve G3TXQ; /archives//html/Towertalk/2008-08/msg00498.html (7,589 bytes)
4. Re: [TowerTalk] Connector Loss Question (score: 1): Author: N7KA@comcast.net; Date: Tue, 26 Aug 2008 12:19:28 +0000; Here is some differnt info. http://www.amphenolrf.com/products/typen.asp?N=0&sid=48B3478041F8E17F _______________________________________________ _______________________________________________ Tower; /archives//html/Towertalk/2008-08/msg00499.html (8,652 bytes)
5. Re: [TowerTalk] Connector Loss Question (score: 1): Author: jimlux <jimlux@earthlink.net>; Date: Tue, 26 Aug 2008 06:18:41 -0700; I suspect that 0.5 is an approximation (i.e. it's probably not 0.50000), and expression in the first place is based on an assumption that the loss is entirely due to ohmic losses (probably reasonable; /archives//html/Towertalk/2008-08/msg00500.html (8,856 bytes)
6. Re: [TowerTalk] Connector Loss Question (score: 1): Author: jimlux <jimlux@earthlink.net>; Date: Tue, 26 Aug 2008 06:20:47 -0700; That data (0.15 dB @ 10 GHz) implies that the K in Joe's equation should be a bit less than 0.05, rather than 0.5 _______________________________________________ _____________________________________; /archives//html/Towertalk/2008-08/msg00501.html (8,147 bytes)
7. Re: [TowerTalk] Connector Loss Question (score: 1): Author: "Joe Reisert, W1JR" <W1JR@arrl.net>; Date: Tue, 26 Aug 2008 20:23:18 -0400; Steve etal, Sorry but the 0.5 in the first line on losses. That was obviously a typo. It should have been 0.05. You can see that by seeing that I gave an example and that value is correct. Thanks for; /archives//html/Towertalk/2008-08/msg00506.html (9,199 bytes)

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