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1. [TowerTalk] How a folded dipole works (score: 1): Author: Martin Ewing <martin.s.ewing@gmail.com>; Date: Tue, 25 Aug 2009 21:10:10 -0400; In an off-line discussion, we were talking about building a folded dipole out of twin lead or ladder line. Some folks may have the idea that if you build an FD out of 450 ohm ladder line, you get a 4; /archives//html/Towertalk/2009-08/msg00523.html (7,973 bytes)
2. Re: [TowerTalk] How a folded dipole works (score: 1): Author: Steve Hunt <steve@karinya.net>; Date: Wed, 26 Aug 2009 11:47:52 +0100; Martin, Just one point of detail. If you construct a folded dipole of wire which has a low(ish) differential-mode characteristic impedance, and which has a significant difference between its differen; /archives//html/Towertalk/2009-08/msg00526.html (10,172 bytes)
3. Re: [TowerTalk] How a folded dipole works (score: 1): Author: Martin Ewing <martin.s.ewing@gmail.com>; Date: Wed, 26 Aug 2009 10:03:11 -0400; Steve, Thanks for pointing this out. Adding more elements to a system adds degrees of freedom that can add complexities to the analysis. My claim that the currents in both wires are equal was obvious; /archives//html/Towertalk/2009-08/msg00533.html (11,526 bytes)
4. Re: [TowerTalk] How a folded dipole works (score: 1): Author: Steve Hunt <steve@karinya.net>; Date: Wed, 26 Aug 2009 19:43:01 +0100; Martin, I agree - it's a good way of explaining how the impedance transformation arises. But it's important to realise that, even when you're not using zip cord, the currents in the two wires are NOT; /archives//html/Towertalk/2009-08/msg00536.html (8,030 bytes)
5. Re: [TowerTalk] How a folded dipole works (score: 1): Author: "Tod - ID" <tod@k0to.us>; Date: Wed, 26 Aug 2009 12:47:10 -0600; Boy, I certainly don't have the 'first principles' for analysis of multi-wire dipoles in hand, but I do recall older versions of the Antenna Book covering that topic. Selection of number of wires and; /archives//html/Towertalk/2009-08/msg00537.html (8,142 bytes)
6. Re: [TowerTalk] How a folded dipole works (score: 1): Author: n8de@thepoint.net; Date: Wed, 26 Aug 2009 21:20:30 -0400; Remember that the impedance ratio is dependent upon the sizes of the parallel wires in the folded dipole. If one wire has a different diameter from one or more of the others, the impedance ratio will; /archives//html/Towertalk/2009-08/msg00542.html (13,311 bytes)

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