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1. [TowerTalk] Slight correction (score: 1): Author: n3rr@erols.com (Bill Hider); Date: Sun, 10 Jun 2001 02:17:26 +0100; "the integral from 0 to Dia of 1/2 surface area of each tube (0.5 x Pi x Dia), where Dia is the Outside diameter of the tube" This is because only one side of the tube is exposed to the wind at any t; /archives//html/Towertalk/2001-06/msg00162.html (7,065 bytes)

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