Does anybody know the formula for calculating the characteristic impedance of a transmission line consisting of 2 parallel square conductors (in air)? Thanks - Paul KW7Y _____________________________
Paul et al: Here's one equation for round conductors: http://emc.ice.uec.ac.jp/~xiao/Wire/index.html , and scroll down the page a bit. Would that be adequate? 73 de Gene Smar AD3F Does anybody know t
Thanks, but I need it very accurate so need the equation for square. - Paul _______________________________________________ _______________________________________________ TowerTalk mailing list Towe
Your best bet is to determine the characteristic impedance for the corresponding microstrip line, and double it. The height above ground plane will be half of the conductor to conductor spacing of th
Most calculators use an approximation like W/h<<1. However my conductors are 2cm square, 3cm center to center, so stripline calculators that I've seen don't work for this situation. - Paul . ________
If you google "square conductor transmission line" several references appear. One of them on the first page claims accurate impedance calculations. 73, Gerald K5GW In a message dated 7/1/2008 2:50:32
--Original Message-- How accurate? There's a number of finite element codes that could give you very accurate results. Also, what's the relative size of the square and the separation (i.e. is the sep
--Original Message-- That's a fairly sophisticated problem, because you need to deal with the material properties (so you can get skin effect right, etc.) ____________________________________________
My conductors are 2cm square, 3cm center to center, - Paul _______________________________________________ _______________________________________________ TowerTalk mailing list TowerTalk@contesting
I found a program called "atlc" (arbitrary transmission line calculator) by searching on Google. If you can wade through how to use it, it supposedly will calculate the transmission line impedance of
I recall an excercise in graduate EM class I took many years ago. You draw the geometry and break it up into squares. Each square has an impedance of 376.7 ohms in free space and you calculate the ch
Good story. Ah... yes... but better than NO credit. I bet it bothered you at the time, wondering if it was a trick question or not. My Philosophy / Logic professor was famous for doing trick question
A quick numerical calculation for squares of side 2cm with 3cm center-center gave me Z0=127.3 Ohms. This assumes perfect conductors. The approximate equation for large spacing is Z0 -> 120*ln(2*separ