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References: [ +subject:/^(?:^\s*(re|sv|fwd|fw)[\[\]\d]*[:>-]+\s*)*\[TowerTalk\]\s+Voltage\s+and\s+SWR\s+\-\s+an\s+ignorant\s+question\s*$/: 4 ]

Total 4 documents matching your query.

1. [TowerTalk] Voltage and SWR - an ignorant question (score: 1)
Author: N4ZR <n4zr@comcast.net>
Date: Fri, 1 Feb 2019 09:41:52 -0500
Last week I was in the 160 CW contest using a jury rigged antenna - my 40M parasitic sloper fed with open wire line from a 4:1 allegedly 5 KW balun via a long run of Buryflex to the shack.  Believe i
/archives//html/Towertalk/2019-02/msg00000.html (7,159 bytes)

2. Re: [TowerTalk] Voltage and SWR - an ignorant question (score: 1)
Author: jimlux <jimlux@earthlink.net>
Date: Fri, 1 Feb 2019 08:32:29 -0800
The swr at the amp's antenna tuner was about 4:1, but when I put 1500 watts on it at the end of the contest the amp would quickly fault indicating an SWR of 20:1.  My guess is that something was flas
/archives//html/Towertalk/2019-02/msg00001.html (8,918 bytes)

3. Re: [TowerTalk] Voltage and SWR - an ignorant question (score: 1)
Author: "john@kk9a.com" <john@kk9a.com>
Date: Fri, 1 Feb 2019 11:57:53 -0500
I thought that 1000 watts into a perfect 50 ohm load is 220V rms. I would expect 4:1 SWR to be higher than your calculated 450v. 450v should not damage N4ZR's antenna system, I would look at the tune
/archives//html/Towertalk/2019-02/msg00002.html (8,807 bytes)

4. Re: [TowerTalk] Voltage and SWR - an ignorant question (score: 1)
Author: jimlux <jimlux@earthlink.net>
Date: Fri, 1 Feb 2019 10:20:37 -0800
I calculated RMS, not peak. P = E^2/R so E = sqrt(P*R) = sqrt(200 * 1000) = 447.2 Vrms *1.4 for 630V peak. That's for 1000W into 200 Ohms.. That probably isn't the voltage though. It really depends o
/archives//html/Towertalk/2019-02/msg00003.html (11,255 bytes)


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