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1. [TowerTalk] Dipole Question (score: 1): Author: csudds@probe.net (Chuck Sudds); Date: Mon, 19 Jul 1999 13:38:27 -0500; Greetings! I am getting ready to put up my W9INN 40/80/160 dipole. I would like to mount it in the horizontal configuration, at the 85ft level off of my tower. The problem is that I only have ONE sui; /archives//html/Towertalk/1999-07/msg00332.html (7,774 bytes)
2. Fw: [TowerTalk] Dipole Question (score: 1): Author: Josh Logan" <jlogan@bewellnet.com (Josh Logan); Date: Mon, 19 Jul 1999 22:19:36 -0600; -- FAQ on WWW: http://www.contesting.com/towertalkfaq.html Submissions: towertalk@contesting.com Administrative requests: towertalk-REQUEST@contesting.com Problems: owner-towertalk@contesting.com Se; /archives//html/Towertalk/1999-07/msg00347.html (8,652 bytes)
3. Fw: [TowerTalk] Dipole Question (score: 1): Author: n4zr@contesting.com (Pete Smith); Date: Tue, 20 Jul 1999 11:03:41 +0100; I agree -- the lazy-V is a great antenna. Only rub is that you need quite a lot of space, because the other end of the "pull-out" rope attached to the center insulator needs to be a LONG way from the; /archives//html/Towertalk/1999-07/msg00351.html (8,255 bytes)
4. [TowerTalk] Dipole Question (score: 1): Author: jreid@aloha.net (Jim Reid); Date: Mon, 24 May 1999 12:53:00 -1000; Hi, Suppose a 20 meter, 1/2 wave long dipole is also 1/2 wave above the ground. Feed point R is somewhere around 60 to 70 some ohms, and the radiation pattern is sort of cardioid, null off the ends,; /archives//html/Towertalk/1999-05/msg00352.html (8,668 bytes)
5. [TowerTalk] Dipole Question (score: 1): Author: jreid@aloha.net (Jim Reid); Date: Tue, 25 May 1999 06:46:17 -1000; Aloha Eric, And thank you so much for your modeling and explanations!! This goes a long way toward adding to my understanding of antennas vs. the various configurations we amateurs have tried, with t; /archives//html/Towertalk/1999-05/msg00358.html (11,483 bytes)
6. [TowerTalk] dipole question (score: 1): Author: "Merlin-7 KI4ILB" <merlin-7@sc.rr.com>; Date: Tue, 19 Jul 2005 20:42:39 -0400; I am new to ham so forgive me if this is a dumb question. I have an inverted v parallel dipole, my question is about grounding. It is fed with 50 ohm coax to the top of my tower. I have a spark gap l; /archives//html/Towertalk/2005-07/msg00465.html (6,915 bytes)
7. Re: [TowerTalk] dipole question (score: 1): Author: "Tom Rauch" <w8ji@contesting.com>; Date: Wed, 20 Jul 2005 06:56:19 -0400; connected to the shield do anything if the outside of the sparkgap is grounded? In an ideally operating unbalanced feedline, current entering or leaving the shield at either end would always be equa; /archives//html/Towertalk/2005-07/msg00467.html (8,960 bytes)
8. Re: [TowerTalk] dipole question (score: 1): Author: Peter Dougherty <w2irt@nac.net>; Date: Wed, 20 Jul 2005 11:02:34 -0400; Hi Tom, This brings up a question I was about to pose to the list myself! In my new QTH, the tower is at the back of the house (an existing base with new tower). I will ground each leg and bind them; /archives//html/Towertalk/2005-07/msg00474.html (8,369 bytes)
9. Re: [TowerTalk] dipole question (score: 1): Author: "Tom Rauch" <w8ji@contesting.com>; Date: Thu, 21 Jul 2005 00:41:44 -0400; existing base with but the through the Most lightning hits strike power lines and ground through wells, plumbing, towers, or other grounds more massive than the pee-poor grounds used on utilities. T; /archives//html/Towertalk/2005-07/msg00494.html (8,840 bytes)
10. Re: [TowerTalk] dipole question (score: 1): Author: "Al Williams" <alwilliams@olywa.net>; Date: Fri, 22 Jul 2005 09:14:58 -0700; I appreciate the explanation given, but (I and maybe others) would like a follow-on of what is happening to this outside-of-the-shield current and how significant is it? 2. The current flowing on the; /archives//html/Towertalk/2005-07/msg00560.html (8,735 bytes)
11. Re: [TowerTalk] dipole question (score: 1): Author: "David Robbins K1TTT" <k1ttt@arrl.net>; Date: Fri, 22 Jul 2005 18:42:03 -0000; Its not really a loss. It is current that would otherwise be on the other side of the dipole. The problem with it is: 1. it takes away from the desired pattern 2. is often the wrong polarization 3. a; /archives//html/Towertalk/2005-07/msg00564.html (10,756 bytes)
12. Re: [TowerTalk] dipole question (score: 1): Author: "Al Williams" <alwilliams@olywa.net>; Date: Fri, 22 Jul 2005 12:14:27 -0700; Thanks for the response. Actually I put this posting in my outbox thinking that I could at a later time edit it for a more clear posting, but apparently the outbox is the place to hold things for lat; /archives//html/Towertalk/2005-07/msg00565.html (12,454 bytes)
13. Re: [TowerTalk] dipole question (score: 1): Author: "Dudley Chapman" <chief@thechief.com>; Date: Fri, 22 Jul 2005 18:57:03 -0400; Al, The answer to your question of how much feedline radiation to expect is much less mysterious than people think. The most important point is that rf current on the outside of the coax shield is co; /archives//html/Towertalk/2005-07/msg00582.html (12,301 bytes)
14. Re: [TowerTalk] dipole question (score: 1): Author: "Tom Rauch" <w8ji@contesting.com>; Date: Fri, 22 Jul 2005 23:59:37 -0400; have an opposite the antenna that It can be in either or both halves of the antenna. diverted to the antenna--an Power division might be difficult to measure or determine. Antennas radiate by ampere; /archives//html/Towertalk/2005-07/msg00599.html (9,247 bytes)

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