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Total 6 documents matching your query.

1. [Towertalk] Strength of fiberglass. (score: 1): Author: wb9uwa@gte.net (WB9UWA Jim Shaffer); Date: Fri, 1 Mar 2002 18:37:27 -0600; Ok, How about an educated guess, then? Jim Shaffer, WB9UWA. held stories fiberglass, something; /archives//html/Towertalk/2002-03/msg00013.html (7,926 bytes)
2. [Towertalk] Strength of fiberglass. (score: 1): Author: wb9uwa@gte.net (WB9UWA Jim Shaffer); Date: Thu, 28 Feb 2002 13:45:57 -0600; Hi All, I am designing a VHF yagi array and strongly considering using fiberglass for the booms. Does anyone have a strength rating for fiberglass that is useful to the layman? For example, if 10 fee; /archives//html/Towertalk/2002-02/msg00681.html (7,653 bytes)
3. [Towertalk] Strength of fiberglass. (score: 1): Author: n8de@thepoint.net (Don Havlicek); Date: Thu, 28 Feb 2002 09:50:01 -0500; Solid fiberglass rod is HEAVY .. much heavier than the same length/diameter of aluminum. Don N8DE; /archives//html/Towertalk/2002-02/msg00683.html (8,316 bytes)
4. [Towertalk] Strength of fiberglass. (score: 1): Author: ac7nj@yahoo.com (Randy Williamson); Date: Thu, 28 Feb 2002 07:17:43 -0800; Solid is not stronger than hollow as it was explained to me its about surface area. What would be interesting is carbon fiber and epoxy resin over a round mold. Randy AC7NJ --Original Message-- From:; /archives//html/Towertalk/2002-02/msg00686.html (9,235 bytes)
5. [Towertalk] Strength of fiberglass. (score: 1): Author: n8de@thepoint.net (Don Havlicek); Date: Thu, 28 Feb 2002 12:03:01 -0500; If someone is looking for STRONG fiberglass booms .. try your local High School track coach .. ask him if he has any old or broken pole-vaulting poles that he would like to get rid of ... tell him yo; /archives//html/Towertalk/2002-02/msg00688.html (10,863 bytes)
6. [Towertalk] Strength of fiberglass. (score: 1): Author: n4kg@juno.com (n4kg@juno.com); Date: Thu, 28 Feb 2002 16:11:20 -0600; WRONG !!! (see below) The maximum shear stress Tau (max) for a hollow tube is Tau (max) = 16 Mt x D / pi (D^4 - d^4) ... (4th power of D and d) where D is the Outside Diameter d is the Inside diamete; /archives//html/Towertalk/2002-02/msg00697.html (8,137 bytes)

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