Could it be Because Zc of a 1000µf as a function of Frequency, the transient
presents generaly a very high freq ( when you turn on the high voltage ) the
current would be that high with a 2500V ( maybe several hundreds of Amperes
for a very short moment ) Maybe it would be possible to satelise a capacitor
with this very short power hi hi .
Mathematicaly its easy to show all this, but ..........you need some
derivative and integral calculation.........and the theory of the " Fourier
serials ".
A simple way to retain this phenomea is to consider the internal resistance
of a capastor equals 0 ohms. when turning on the power supply, then apply
ohms law..
on4kj jos.
----- Original Message -----
From: "telkom.net" <firson@telkom.net>
To: "Amps Reflector" <amps@contesting.com>
Sent: Friday, November 08, 2002 4:53 PM
Subject: [Amps] Capasitors Question
> In low voltage Power Supply (ie:12 volt) for current amount 1A, it's
usually
> use 1000uF/16volt capacitor for smoothing DC ripple.
> But why in high voltage PS (ie: 2500 volt) for current amount 1A, only use
> 50uF/2500Volt for smoothing DC ripple ??..
> Any body knows why....??
>
> Thanks
> Firson - YD0LZH
>
>
> --------------------------------------------------------------------------
--
> Ikuti polling TELKOM Memo 166 di www.plasa.com dan menangkan hadiah
masing-masing Rp 250.000 tunai
> -------------------------------------------------------------------------
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