According to the 1970 UTC catalog, the specs for their CG-310 Plate Xfmr
are:
4600-4050-3500-0-3500-4050-4600 VAC
4000/3500/3000 VDC @ 600 mA
19-1/4" Long x 10" Wide x 13-1/4" High
Weight: 150 Lbs.
Since this item is listed as a 'Commercial' transformer, one might assume
that these ratings are CCS, Continuous Commercial Service. No ICAS ratings
are listed in this spec.
73, Larry - W1GOR, ARRL 40 year Life Member
----- Original Message -----
From: "Carcia, Francis A HS" <francis.carcia@hs.utc.com>
To: <craxd1@ezwv.com>; <amps@contesting.com>
Sent: Tuesday, May 03, 2005 4:13 PM
Subject: Re: [Amps] Plate transformer current unknown
> Speaking of transformers. Does anyone know the ccs and ICS current ratings
> of a UTC CG310?
> gfz
>
> -----Original Message-----
> From: Will Matney [mailto:craxd1@ezwv.com]
> Sent: Tuesday, May 03, 2005 2:56 PM
> To: amps@contesting.com
> Subject: Re: [Amps] Plate transformer current unknown
>
>
> Angel,
>
> One last thing, since that core is that big, measure the thickness of an
> outside leg. A 4 inch core shows a 2 inch leg, and a 3 inch core shows a
> 1-1/2 inch leg. We might be able to tell from it then.
>
> Best,
>
> Will
>
> *********** REPLY SEPARATOR ***********
>
> On 5/3/05 at 1:38 PM Will Matney wrote:
>
>>Angel,
>>
>>If the transformer stack is 11" wide X 9" high then about the closest
>>thing to a standard EI lam is a 4(3)MH which has a 4 inch center leg and
>>is 10" high X 11-1/8" wide. Now if the stack is 10" deep, that makes 4 X
>>10 = 40 square inches. That sounds a little big to me though as generally
>>a rectangular stack is used mostly which would have been 4 X 8 inches or
>>36 square inches of core area. Anyhow, lets work this backwards;
>>
>>a = 0.16 X sqrt P
>>
>>P = a / 0.16 ^2
>>
>>40 sq in / 0.16 = 250 then 250 ^2 = 62,500 watts. (12 kilogauss at 60 Hz)
>>36 sq in / 0.16 = 225 then 225 ^2 = 50,625 watts. (12 kilogauss at 60 Hz)
>>
>>One should note, I'm not sure as I didn't go back and check, I may have
>>wrote 0.61 for the formula where it should be 0.16. Sorry about that if I
>>did.
>>
>>The turns per volt will roughly be 5 / a or 5 / 40" = 1/8 TPV, and 5 / 36"
>>= 3/16 TPV.
>>
>>Something dont sound right about those measurements for the core, double
>>check those and only measure the core itself (lamination stack W X H X D)
>>as the depth is what I thought about. The next stock lam is a 3" but RCA
>>could have had a custom made like a 3-1/2" leg. For 3-1/2" at 10" deep
>>would be 35 sq in., and for a 3" leg, 30 sq inches. 3-1/2" would be 47,850
>>watts and at 3" would be 35,156 watts. An approximate weight using a 10"
>>stack with the 4(3)MH lam would be 258.75 pounds. By your dimensions
>>given, maybe 200 pounds. If it's that big, it may well be this size in kVA
>>or in watts.
>>
>>3000 x 1.414 = 4242 VDC. 50,000 watts / 4242 VDC = 11.75 amperes (with no
>>losses).
>>
>>Assuming a 5% PS loss, 11.75 X 1.05 = 12.34 amperes.
>>
>>Keep in mind thought that the lead size will be in conduit rating for
>>amperes. Here, 18 gauge is 13 to 18 amps for chassis wiring.
>>
>>Remember that these figures are ballpark ones and not exact.
>>
>>Best,
>>
>>Will
>>
>>*********** REPLY SEPARATOR ***********
>>
>>On 5/3/05 at 12:05 PM Angelo Karabetsos wrote:
>>
>>>I am unable to calculate anything to do with windings or core due to the
>>>fact it is in a metal case encapsulated in black epoxy. I discovered this
>>>after removing the lid. I'll say one thing, it's darn heavy and hard to
>>>move
>>>around without anywhere to grab. The secondary wire gauge looks to be
>>>about
>>>18ga and the dimensions are 11"x9"x10" and has a RCA nameplate. Not too
>>>much
>>>more information I can determine. Now I know what to look for at flea
>>>markets.
>>>One other question. What should the B+ voltage be after rectification.
>>>Lets
>>>say 3000v secondary through a fullwave bridge rectifier and a bank of ten
>>>470uf 450v caps? I read somewhere to multiply by 0.9 and that should be a
>>>good rule of thumb. What I am trying to determine is how to calculate the
>>>proper transformer for the job and keep voltage drop under load to
>>>respectable figure. Not an easy task to figure out with surplus parts.
>>>
>>>Angelo
>>>
>>>>From: "Will Matney" <craxd1@ezwv.com>
>>>>Reply-To: craxd1@ezwv.com
>>>>To: amps@contesting.com
>>>>Subject: Re: [Amps] Plate transformer current unknown
>>>>Date: Fri, 29 Apr 2005 11:28:25 -0400
>>>>
>>>>Angelo,
>>>>
>>>>Really you cant tell that way (using the resistance) unless you know
>>>the
>>>mean lenght of turn, how many turns per layer, and how many layers they
>>>are
>>>in the winding. This then would give you how long the wire is and you
>>>could
>>>then use the resistance and the length to determine the wire size. If
>>it's
>>>possible to use a micrometer or a wire gauge to see what the secondary
>>>wire
>>>size is, then one can find out what its rating is. In amateur service,
>>>ICAS
>>>used anywhere from 700 to 900 circular mils per ampere. CCS uses anyhwere
>>>from say 1000 to 1200 cir. mil. per amp. If you can find the wire size,
>>go
>>>look at a wire chart for how many circular mils it has and divide by the
>>>above numbers to determine its current carrying ability. IE, 10,000
>>>circular
>>>mils running at 1000 cir mil per amp = 10 amperes.
>>>>
>>>>Best,
>>>>
>>>>Will
>>>>
>>>>
>>>>*********** REPLY SEPARATOR ***********
>>>>
>>>>On 4/29/05 at 3:01 PM Angelo Karabetsos wrote:
>>>>
>>>> >I would like to find out the current rating of a transformer.
>>>Primary
>>>> >voltage taps 0v-110v-115v-208v-230v and secondary taps
>>>3450v-0v-3450v and
>>>> >secondary resistance of 53.5ohms from 0v to 3450v tap and
>>107ohms
>>>from
>>>> >3450v
>>>> >to 3450v tap. All measurements done with a simple DMM. The
>>>commercial
>>>> >amplifier it came out of has a plate current meter with a max
>>>reading of
>>>> >600ma. How could I find out the CCS or ICAS rating?
>>>> >Cheers Angelo
>>>> >
>>>>
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>>
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