Does anybody know the relationship between Q and SWR for a PI network? For example let's say I design my amp PI output network for 7.0MHz. I simulate the Tube Impedance with a 1K resistor. I put my M
<Does anybody know the relationship between Q and SWR for a PI network? <For example let's say I design my amp PI output network for 7.0MHz. I <simulate the Tube Impedance with a 1K resistor. I put m
I found an online calculator http://chemandy.com/calculators/return-loss-and-mismatch-calculator.htm A resistive load of 300 Ohm in a 50 Ohm System represents about a 3dB loss over a 50 Ohm load. A r
Should be 212+j212 I believe to produce impedance of 300 Ohms. Bill I found an online calculator http://chemandy.com/calculators/return-loss-and-mismatch-calculator.htm <https://na01.safelinks.protec
There is a relationship between SWR bandwidth, and Q which is valid for "simple" circuits and for limited excursions from the center frequency. It uses the limit of |X| = R of the input impedance, an
Thanks for the info. The calculator I used gave the answer 6:1. but my test circuit gave about 4:1 on my MFJ259 http://chemandy.com/calculators/return-loss-and-mismatch-calculator.htm - Paul Q = cent
212+j212 is a Zmag of 300, but that doesn't equate to a 6:1 VSWR with a Z0 of 50 ohms; it's 8.6:1 VSWR. I think the previous poster was trying to compare two different complex Z's that both yielded