>Rich,
>
>you say
>
>>However if Zout is 50 ohms and the load is 50 ohms, the efficiency is
>>50%, not the 62 or so percent that we typically see. It seems to me that
>>62% efficiency would mean that Zout was 30 ohms.
>>Rich...
>
>When we were discussing this matter here a few weeks ago, Tom indicated
>(although I may have misunderstood him) that the the output impedance is
>a 'non dissipative resistance'. Under those circumstances, the
>efficiency would be different.
>
Non-dissipative resistance makes no sense to me, Peter. What next,
non-reactive inductance?
During the vhf parasitics debate, Mr. Rauch indicated that standard AC
Circuit Analysis could not be used to calculate the distribution of vhf
currents in a vhf parasitic-suppressor.
R. L. Measures, 805-386-3734, AG6K
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